All categories

3 years ago

I'll give brainliest to the best answer!!

Chemistry

2 answers:

andreyandreev [35.5K]3 years ago

7 0

Answer:

A strong alkali is 100% ionised.eg÷sodium hydroxide.

A week alkali is not 100% ionised.eg÷ammonia

A concentrated acid contains a large amount of acid in a given volume.

Inessa [10]3 years ago

3 0

Answer-1:

A strong alkali dissociates completely to form OH- ions. A weak alkali only partially dissociates to form OH- ions. An example of a strong alkali is is sodium hydroxide.

Answer-2

If the number of certain moles in per litre of a molecule is more then the acidic substance is known as concentrated acid. For example : In dilute solution of H2SO4 the concentration of acid is 2% and 98% water.

You might be interested in

Why is copper (i) sulfate Cu2So4^-2? not copper (ii)?

const2013 [10]

Copper (I) oxidation state is 1 Cu2So4
copper (II) oxidation state is +2 CuSo4
copper (i) also give up one electron so you need two of them to react with the sulfate ion (which has charge of -2)
and also all metallic ions have an multiple oxidation levels corresponding to the number of electrons they can exchange or loose
Hope this helps

5 0

3 years ago

Read 2 more answers

What are the safety procedures for nuclear accidents nowadays?

Zigmanuir [339]

Explanation:

Take shelter in a hard wall building

Close doors and windows cut off ventilation

4 0

3 years ago

What is the most important monosaccharide on Earth?

Nikolay [14]

Probably the most important monosaccharide on earth is Glucose. it is used in many bodily functions and it a key source of energy

5 0

3 years ago

Calculate the number of grams of oxygen gas in a 24L container at STP

romanna [79]

There are 34 g of oxygen in the container.

We can use the<em> Ideal Gas Law</em> to solve this problem.

$pV = nRT$

But $n = \frac{m}{M}$ , so

$pV = \frac{m}{M}RT$ and

$m = \frac{pVM}{RT}\\$

STP is 0 °C and 1 bar, so

$m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\$

7 0

3 years ago

Calculate the molarity of a MgSosolution

svet-max [94.6K]

Answer:

Explanation:

because

7 0

2 years ago