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fomenos
3 years ago
16

A circuit is built based on the circuit diagram shown.

Physics
2 answers:
DaniilM [7]3 years ago
9 0

Answer : Current in 50 ohms resistor is 1.2 A.

Explanation :

It is given that,

Voltage, V=60\ V

In the given figure, all three resistors i.e. 40 ohms, 50 ohms and 30 ohms are in parallel combination.

We know that in parallel combination, the voltage in all resistor remains the same.

From Ohm's law :

V = I R

V = voltage

I = current

R = resistors

So, the current in 50 ohm resistor will be :

I=\dfrac{V}{R}

I=\dfrac{60\ V}{50\ \Omega}

I=1.2\ A

So, the current flowing in 50 ohms resistor is 1.2 A.

liraira [26]3 years ago
3 0
The correct answer is A <span />
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g The steam above a freshly made cup of instant coffee is really water vapor droplets condensing after evaporating from the hot
geniusboy [140]

Answer:

the final temperature = 74.33°C

Explanation:

Using the expression Q = mcΔT for the heat transfer and the change in temperature .

Here ;

Q = heat transfer

m = mass of substance

c = specific heat

ΔT = the change in temperature

The heat Q required to change the phase of a sample mass  m is:

Q = mL_v

where;

L_v  is the latent heat of vaporization.

From the question ;

Let M represent the mass of the coffee that remains after evaporation is:

ΔT = \frac{mL_v}{MC}

where;

m = 2.50 g

M = (240 - 2.50) g  = 237.5 g

L_v  = 539 kcal/kg

c = 1.00kcal/kg. °C

ΔT = \frac{2.50*539 \ kcal /kg}{237.5 g *1.00 \ kcal/kg . ^0C}

ΔT = 5.67°C

The final temperature of the coffee is:

T_f = T_i - ΔT

where ;

T_I = initial temperature = 80 °C

T_f = (80 - 5.67)°C

T_f =  74.33°C

Thus; the final temperature = 74.33°C

8 0
3 years ago
Read 2 more answers
the displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s
12345 [234]

The average velocity or displacement of a particle for the first time interval is <u>Δs / Δt = 6 cm/s.</u>

Solution:

As we know that displacement is calculated in centimeters and the unit of time is second.

The average velocity for the first interval [1,2] is given

Δs / Δt = s (t2) - s (t) / t2 - t1

Δs / Δt = 2sin2  π  + 3cos 2 π -  ( 2sin π + 3cos π ) / 2 - 1

Δs / Δt = 2(0) + 3(1) - 2(0) - 3 (-1) / 1

Δs / Δt = 6 cm/s

Thus the average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s

If you need to learn more about displacement click here:

brainly.com/question/28370322

#SPJ4

The complete question is:

The displacement of a particle moving back and forth along a line is given by the following equation s(t) = 2sin π t + 3cos π t. Estimate the instantaneous velocity of the particle when t = 1

4 0
2 years ago
A 75Kg man jumps from a window 1.0m above the sidewalk. If the man falls with his knees and ankles locked, the only cushion for
liq [111]

Answer:

150153.06122 N

Explanation:

m = Mass of person = 75 kg

h = Height of fall = 1 m

g = Acceleration due to gravity = 9.81 m/s²

F = Force

s = Displacement = 0.49 cm

Potential energy is given by

P=mgh\\\Rightarrow P=75\times 9.81\times 1\\\Rightarrow P=735.75\ J

Work is given by

W=Fs\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{735.75}{0.0049}\\\Rightarrow F=150153.06122\ N

The average force exerted is 150153.06122 N

8 0
3 years ago
HELP URGENT- will give brainliest if correct
fredd [130]

Answer:

6 km is the right answer

hope it helps you

Explanation:

please mark me as brainliest

3 0
3 years ago
A long, hollow, cylindrical conductor (inner radius 3.4 mm, outer radius 7.3 mm) carries a current of 36 A distributed uniformly
Elden [556K]

Answer:

a. B= 9.45 \times10^{-3} T

b. B= 0.820 T

c. B= 0.0584 T

Explanation:

First, look at the picture to understand the problem before to solve it.

a. d1 = 1.1 mm

Here, the point is located inside the cilinder, just between the wire and the inner layer of the conductor. Therefore, we only consider the wire's current to calculate the magnetic field as follows:

To solve the equations we have to convert all units to those of the international system. (mm→m)

B=\frac{u_{0}I_{w}}{2\pi d_{1}} =\frac{52 \times4\pi \times10^{-7} }{2\pi 1.1 \times 10^{-3}} =9.45 \times10^{-3} T\\

μ0 is the constant of proportionality

μ0=4πX10^-7 N*s2/c^2

b. d2=3.6 mm

Here, the point is located in the surface of the cilinder. Therefore, we have to consider the current density of the conductor to calculate the magnetic field as follows:

J: current density

c: outer radius

b: inner radius

The cilinder's current is negative, as it goes on opposite direction than the wire's current.

J= \frac {-I_{c}}{\pi(c^{2}-b^{2}  ) }}

J=\frac{-36}{\pi(5.33\times10^{-5}-1.16\times10^{-5}) } =-274.80\times10^{3} A/m^{2}

B=\frac{u_{0}(I_{w}-JA_{s})}{2\pi d_{2} } \\A_{s}=\pi (d_{2}^{2}-b^2)=4.40\times10^{-6} m^2\\

B=\frac{6.68\times10^{-5}}{8.14\times10^{-5}} =0.820 T

c. d3=7.4 mm

Here, the point is located out of the cilinder. Therefore, we have to consider both, the conductor's current and the wire's current as follows:

B=\frac{u_{0}(I_w-I_c)}{2\pi d_3 } =\frac{2.011\times10^-5}{3.441\times10^{-4}} =0.0584 T

As we see, the magnitud of the magnetic field is greater inside the conductor, because of the density of current and the material's nature.

3 0
3 years ago
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