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fomenos
3 years ago
16

A circuit is built based on the circuit diagram shown.

Physics
2 answers:
DaniilM [7]3 years ago
9 0

Answer : Current in 50 ohms resistor is 1.2 A.

Explanation :

It is given that,

Voltage, V=60\ V

In the given figure, all three resistors i.e. 40 ohms, 50 ohms and 30 ohms are in parallel combination.

We know that in parallel combination, the voltage in all resistor remains the same.

From Ohm's law :

V = I R

V = voltage

I = current

R = resistors

So, the current in 50 ohm resistor will be :

I=\dfrac{V}{R}

I=\dfrac{60\ V}{50\ \Omega}

I=1.2\ A

So, the current flowing in 50 ohms resistor is 1.2 A.

liraira [26]3 years ago
3 0
The correct answer is A <span />
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A tennis ball travelling at a speed of 46m/s with a mass of 58kg. Calculate the kinetic<br>energy​
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its 1/2 the mass of the object times by its velocity ^ 2

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How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?​
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3 years ago
While in a car at 4.47 meters per second a passenger drops a ball from a height of 0.70 meters above the top of a bucket how far
viktelen [127]

Answer:

1.7 m

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u_y = Velocity of ball in y direction = 0

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

t = Time taken

s_y = Vertical displacement = 0.7 m

s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.7=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{0.7\times 2}{9.81}}\\\Rightarrow t=0.38\ \text{s}

Horizontal displacement is given by

s_x=v_xt\\\Rightarrow s_x=4.47\times 0.38\\\Rightarrow s_x=1.7\ \text{m}

The passenger should throw the ball 1.7 m in front of the bucket.

5 0
3 years ago
Atoms of two different elements must have different
sergejj [24]

Explanation:

C. Atomic numbers....

4 0
3 years ago
Two cars are moving towards each other and sound emitted by first car with real frequency of 3000 hertz is detected by a person
sertanlavr [38]

Answer:

 v ’= 21.44 m / s

Explanation:

This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s

           f ’= f (v + v₀) / (v-v_{s})

where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer

in this exercise both the source and the observer are moving, we will assume that both have the same speed,

                v₀ = v_{s} = v ’

we substitute

               f ’= f (v + v’) / (v - v ’)

               f ’/ f (v-v’) = v + v ’

               v (f ’/ f -1) = v’ (1 + f ’/ f)

               v ’= (f’ / f-1) / (1 + f ’/ f) v

               v ’= (f’-f) / (f + f’) v

let's calculate

                v ’= (3400 -3000) / (3000 +3400) 343

                v ’= 400/6400 343

                v ’= 21.44 m / s

3 0
3 years ago
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