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Nataly_w [17]
3 years ago
11

If the student hit a drum in his bedroom how would the sound wave behave differently than if he hit it in a swimming pool? Pleas

e respond in full sentences. Make sure you use the words faster, slower, medium, air, water in your answer.
Physics
1 answer:
zlopas [31]3 years ago
4 0
The sound wave would behave differently in a swimming pool than in his bedroom because sound waves travel faster in more dense mediums; such as water. The wave will travel faster in water, and slower in air.
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The nebula hypothesis of the formation of the solar system assumes that the material that became the solar system began as a lar
Zinaida [17]

Answer:

Option (D)

Explanation:

According to the nebula hypothesis that explains the formation of solar system, there occurs changes in terms of its shape as well as the rate of rotation. It is because of the conservation of angular momentum.

The total angular momentum comprising a system remains same or constant, throughout its period of rotation in the absence of net torque. Due to the increasing density, the nebula eventually collapses, and these clouds of gases collides with one another and forms a large cloud. These clouds attains an average velocity and results in an orderly motion, which eventually take the shape of a disk. This is how with time, the sun and the planets have formed, comprising the solar system.

Thus, the correct answer is option (D).

6 0
3 years ago
A force can exist between two charged particles or objects even if they're as small as subatomic particles. Between which of the
aev [14]
I think it is a not sher
7 0
3 years ago
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malfutka [58]

Acceleration is the rate of change in an object's velocity

3 0
3 years ago
Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

4 0
3 years ago
The moment of inertia for a 5500 kg solid disc is 12100 kg-m^2. Find the radius of the disc? (a) 2.111 m (b) 2.579 m (c) 1.679
Soloha48 [4]

Answer:

The radius of the disc is 2.098 m.

(e) is correct option.

Explanation:

Given that,

Moment of inertia I = 12100 kg-m²

Mass of disc m = 5500 kg

Moment of inertia :

The moment of inertia is equal to the product of the mass and square of the radius.

The moment of inertia of the disc is given by

I=\dfrac{mr^2}{2}

Where, m = mass of disc

r = radius of the disc

Put the value into the formula

12100=\dfrac{5500\times r^2}{2}

r=\sqrt{\dfrac{12100\times2}{5500}}

r= 2.098\ m

Hence, The radius of the disc is 2.098 m.

8 0
3 years ago
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