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andriy [413]
2 years ago
13

The nebula hypothesis of the formation of the solar system assumes that the material that became the solar system began as a lar

ge spherical cloud of gas and dust, rotating slowly. As the solar system formed, most of this material was transformed into a compact, flattened disk, rotating more rapidly. What is the explanation for this change in shape and rate of rotation?
A. the influence of nearby stars
B. differentiation of materials easily vaporized and not easily vaporized
C. alignment with the plane of the Milky Way Galaxy
D. conservation of angular momentum
Physics
1 answer:
Zinaida [17]2 years ago
6 0

Answer:

Option (D)

Explanation:

According to the nebula hypothesis that explains the formation of solar system, there occurs changes in terms of its shape as well as the rate of rotation. It is because of the conservation of angular momentum.

The total angular momentum comprising a system remains same or constant, throughout its period of rotation in the absence of net torque. Due to the increasing density, the nebula eventually collapses, and these clouds of gases collides with one another and forms a large cloud. These clouds attains an average velocity and results in an orderly motion, which eventually take the shape of a disk. This is how with time, the sun and the planets have formed, comprising the solar system.

Thus, the correct answer is option (D).

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Help is requested. Will give brainliest to anyone who answers correctly. 
sp2606 [1]
The answer should be d because they are constantly rotating
4 0
3 years ago
For a particular casting setup, the top of the sprue has a diameter of 0.030 m, and its length is 0.200 m. The volume flow rate
faust18 [17]

Answer with Explanation:

We are given that

Diameter=0.030 m

Length of sprue=h_1=0.200 m

Metal volume flow  rate,Q=0.03m^3/min

Q=\frac{0.03}{60}=5\times 10^{-4}m^3/s because 1 minute=60 seconds

Let 1 for the top and 2 for the bottom

d_=0.030 m

h_2=0

A_1=\frac{\pi d^2}{4}=\frac{3.14\times (0.030)^2}{4}

A_1=7.065\times 10^{-4} m^2

v_1=\frac{Q}{A_1}=\frac{5\times 10^{-4}}{7.065\times 10^{-4}}

v_1=0.708 m/s

Pressure at the top and bottom of the sprue is atmospheric

h_1+\frac{v^2_1}{2g}=h_2+\frac{v^2_2}{2g}

Substitute the values

0.2+\frac{(0.708)^2}{2\cdot 9.8}=0+\frac[v^2_2}{2\cdot 9.8}

v^2_2=2\cdot 9.8\cdot \frac{0.2\cdot 9.8\cdot 2+0.501264}{2\cdot 9.8}=4.421264

v_2=\sqrt{4.421264}=2.1 m/s

Q=A_2v_2

5\times 10^{-4}=A_2\times 2.1

A_2=\frac{5\times 10^{-4}}{2.1}=2.381\times 10^{-4} m^2

Reynolds number=\frac{v_2D\rho}{\eta}

\eta=0.004 N.s/m^2

\rho=2700 kg/m^3

Substitute the values then we get

Reynolds number=\frac{2.1\times 0.03\times 2700}{0.004}

Reynolds number=42525

The Reynolds number is greater than 4000 .Therefore, the flow is turbulent.

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3 years ago
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Answer:

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Explanation:

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fomenos
Sound waves (m)

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3 years ago
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Explanation:

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