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sertanlavr [38]
3 years ago
10

A long, straight wire carries a current of 8.60

Physics
1 answer:
Kay [80]3 years ago
6 0

First of all, we need to calculate the magnetic field generated by the wire at a distance r=3.90 cm=0.039 m, which is given by:

B=\frac{\mu_0 I}{2 \pi r}

where I=8.60 A is the current. Substituting numbers in the equation, we find

B=\frac{(4 \pi \cdot 10^{-7})(8.6 A)}{2 \pi (0.039 m)}=4.4 \cdot 10^{-5} T

And now we can calculate the force exerted on the electron, which is given by:

F=qvB

where q=1.6 \cdot 10^{-19} C is the charge of the electron and v=5.0 \cdot 10^4 m/s is its speed. Substituting data in the formula, we find

F=(1.6 \cdot 10^{-19}C)(5.00 \cdot 10^4 m/s)(4.4 \cdot 10^{-5} T)=3.5 \cdot 10^{-19} N

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