The answer to this question is 3.69
The formula for this problem that we will be using is:
F * cos α = m * g * μs where:F = 800m = 87g = 9.8
cos α = m*g*μs/F= 87*9.8*0.55/800= 0.59 So solving the alpha, find the arccos above.
α = arccos 0.59 = 54 ° is the largest value of alpha
The distance traveled by the hockey player is 0.025 m.
<h3>The principle of conservation of linear momentum;</h3>
- The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.
The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;
The time taken for the puck to reach 15 m is calculated as follows;
The distance traveled by the hockey player at the calculated time is;
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?
Answer:
1977.696 J
Explanation:
Given;
Weight of the box = 28.0 kg
Force applied by the boy = 230 N
angle between the horizontal and the force = 35°
Therefore,
the horizontal component of the force = 230 × cosθ
= 230 × cos 35°
= 188.405 N
Coefficient of kinetic friction, μ = 0.24
Force by friction, f = μN
here,
N = Normal force = Mass × acceleration due to gravity
or
N = 28 × 9.81 = 274.68 N
therefore,
f = 0.24 × 274.68
or
f = 65.9232 N
Now,
work done by the boy, W₁ = 188.405 N × Displacement
= 188.405 N × 30
= 5652.15 J
and,
the
work done by the friction, W₂ = - 65.9232 N × Displacement
= - 65.9232 N × 30 m
= - 1977.696 J
[ since the friction force acts opposite to the direction of motion, therefore the workdone will be negative]
