1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alja [10]
3 years ago
6

1)the magnetic field is strongest near_________of a bar magnet.

Physics
2 answers:
rodikova [14]3 years ago
8 0

Answer:

1 . a) the poles

2. a) earth poles.

3. b) attraction.

4. a) magnetite.

5. a) domains.

Explanation:

The magnetic field is strongest at the poles and very weak at the center of the magnet.

The magnetic compass will always align along the north - south poles  of the earth. North of the compass needle is attracted towards the magnetic south pole of the earth.

Magnetic Field lines begin at the north pole of the magnet and end at the south pole. Unlike poles attract and like poles repel , so they curve for unlike poles.

Magnetite is a magnetic mineral, which is present in the animal brains , enabling them to identify correct directions.

Magnetic domains are regions where individual magnetic moments of the atoms are aligned in a definite direction.

horrorfan [7]3 years ago
7 0
1. Is A. at the poles because thats where the magnetic field is going out then coming back into the earth to produce the magnetic field.
2. Again its A. because the compass needle is attracted to " north " which is magnetic south. It does this because opposites attract.
3. This one would be B. Because if the magnets were being repelled the magnetic field lines would look like there was a line that the field hit and bounced off of it.
4. This answer is A. the magnetite helps them migrate so they know which way is north and which way is south.
5. This answer is A. Because without the domains there wouldn't be poles on the magnetic object. <span />
You might be interested in
Ok, so this question is probably really easy but I can't really be bothered to answer it, terrible I know, but I thank all usefu
Dvinal [7]
Without a bulb energy cant go through and it would be an open circuit blocking the energy from coming out.
3 0
3 years ago
lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A
qaws [65]

2.6×10^6\:\text{m}

Explanation:

The acceleration due to gravity g is defined as

g = G\dfrac{M}{R^2}

and solving for R, we find that

R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration F_c experienced by the satellite is equal to the gravitational force F_G or

F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)

The orbital velocity <em>v</em> is the velocity of the satellite around the planet defined as

v = \dfrac{2\pi r}{T}

where <em>r</em><em> </em>is the radius of the satellite's orbit in meters and <em>T</em> is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}

Solving for <em>M</em>, we get

M = \dfrac{4\pi^2 r^3}{GT^2}

Putting this expression back into Eqn(1), we get

R = \sqrt{\dfrac{G}{g}\left(\dfrac{4\pi^2 r^3}{GT^2}\right)}

\:\:\:\:=\dfrac{2\pi}{T}\sqrt{\dfrac{r^3}{g}}

\:\:\:\:=\dfrac{2\pi}{(1.44×10^4\:\text{s})}\sqrt{\dfrac{(5×10^6\:\text{m})^3}{(3.45\:\text{m/s}^2)}}

\:\:\:\:= 2.6×10^6\:\text{m}

5 0
3 years ago
Explain how machines can be useful if the output is always less than the input work
Anni [7]

Because: Some of the work done by the machine is used to overcome the friction created by the use of the machine. ... Work output can never be greater than work input. Machines allow force to be applied over a greater distance, which means that less force will be needed for the same amount of work.

6 0
3 years ago
A punter wants to kick a football so that the football has a total flight time of 4.70s and lands 56.0m away (measured along the
Sindrei [870]

Answer:

Explanation:

How long does the football need to rise?

4.70/3 = 2.35 s

What height will the football reach?

h = ½(9.81)2.35² = 27.1 m

With what speed does the punter need to kick the football?

vy = g•t = 9.81(2.35) = 23.1 m/s

vx = d/t = 56.0/4.70 = 11.9 m/s

v = √(vx²+vy²) = 26.0 m/s

At what angle (θ), with the horizontal, does the punter need to kick the football?

θ = arctan(vy/vx) = 62.7°

3 0
2 years ago
What is the most appropriate tool to use when collecting data from the investigation
NeTakaya
If it is just a reseach investigatory project, you could monitor it by using different variables (controlled), acurate measuring devices and camera for documentations
7 0
3 years ago
Other questions:
  • You are walking on a beach and find a mystery piece of metal. You take it back to your lab and measure its mass to be 0.5 kg. In
    15·1 answer
  • Two piano strings are supposed to be vibrating at 220 Hz, but a piano tuner hears three beats every 2.5 s when they are played t
    12·1 answer
  • If you kick a ball and the ball accelerates through the air, the forces involved must be
    10·2 answers
  • Particle accelerators, such as the Large Hadron Collider, use magnetic fields to steer charged particles around a ring Consider
    14·1 answer
  • 2.1kilograms into grams (1000g=1kg)
    14·1 answer
  • Which of the following is a result of the transfer of energy?
    9·2 answers
  • IN WHAT CONDITION DO SOUND ECHO
    10·1 answer
  • find the following Distance, Time, and Velocity in the problem; a track runs a 100-m dash in 11 seconds. What is his average vel
    6·1 answer
  • Which famous scientist is associated with the force of gravity?
    8·1 answer
  • URGENT PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST !!!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!