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sukhopar [10]
3 years ago
5

In an experiment, the independent variable __________.

Physics
2 answers:
alexira [117]3 years ago
7 0

Answer:The correct answer is option D.

Explanation:

Independent variables are those variables which do not dependent on any other variable.These are those variables which can be controlled or varied by researchers to test their effect on the dependent variables.

Dependent variables are those variables which depends upon independent and other dependent variables.

Hence, from the given the option the correct answer is option D.

joja [24]3 years ago
4 0
D) is manipulated or varied
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nata0808 [166]
I have a note here that might help you solve the problem on your own:

According to the law of conservation of energy 

The energy of the photon is used in overcoming the workfunction of the metal, and the excess energy goes as the kinetic energy of the electron. 

<span>Photon Energy = Work function of Cs + KE of electron 
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I hope my guide has come to your help. God bless and have a nice day ahead!
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A nonconducting ring of radius 10.0 cm is uniformly charged with a total positive charge 10.0μC. The ring rotates at a constant
maw [93]

The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.

The radius of the nonconducting ring is R = 10 cm.

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The ring is x = 5 cm from the center of the ring.

Now,

R = 10 cm = 0.1 m

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x = 5 cm = 0.05 m

The magnetic field on the axis of a current loop is given as:

B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]

Now, I = q / [2π/ω]

So, the magnitude of the magnetic field which is directed away from the center is:

B =  [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]

B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]

B = 1.43 × 10⁻¹⁰ T

B = 143 pT

Learn more about the magnetic field here:

brainly.com/question/14411049

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D.
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