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sukhopar [10]
3 years ago
5

In an experiment, the independent variable __________.

Physics
2 answers:
alexira [117]3 years ago
7 0

Answer:The correct answer is option D.

Explanation:

Independent variables are those variables which do not dependent on any other variable.These are those variables which can be controlled or varied by researchers to test their effect on the dependent variables.

Dependent variables are those variables which depends upon independent and other dependent variables.

Hence, from the given the option the correct answer is option D.

joja [24]3 years ago
4 0
D) is manipulated or varied
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All objects emit electromagnetic radiation and the amount of radiation emitted at each wavelength depend on the temperature of the object. This observation is described by Wien's law, which states that the black body radiation curve for different temperatures peaks at a wavelength that is inversely proportional to the temperature. 
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A wire carries a 2a current. what is the current in a second wire that delivers twice as much charge in the same amount of time?
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Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t
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1. The bowling ball have more potential energy as it sit on top of the building

2.The bowling ball have same potential energy and kinetic energy as it is half way through its fall

3. The bowling ball have more kinetic energy just before it hits the ground

4. The potential energy of the bowling ball as it sits on top of the building is 784J

5. The potential energy of the ball as it is half way through the fall, 20 meters high is 392J

6. The kinetic energy of the ball as it is half way through the fall is 392J

7. The kinetic energy of the ball just before it hits the ground is 784J

Explanation:

Calculating potential energy and kinetic energy for all the instances,

1. ball on top of a 40 meters tall building

Potential energy at the top of building with a height of 40m = mgh

P.E = mgh =2*9.8*40= 784J

At the top pf the building since v=0 kinetic energy is zero

2. half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second

Potential energy when it is half way through fall = mgH

where H represents new height that is equal to 20m

hence P.E=mgH=2*9.8*20= 392J

Kinetic energy  of the ball is \frac{1}{2} mv^{2}  = \frac{1}{2} *2*19.8^{2}=392.04J

3.  Just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.

The potential energy of ball just before it hits the ground = mgh= 2*9.8*0=0J

kinetic energy =\frac{1}{2} mv^{2}= 784J

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3 years ago
What quantity measures the number of complete cycles an oscillation makes per second?
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