Then, it jumps to HIGHER ORBITALS
The answer is true to your question
(a) 764.4 N
The weight of the astronaut on Earth is given by:

where
m is the astronaut's mass
g is the acceleration due to gravity
Here we have
m = 78.0 kg
g = 9.8 m/s^2 at the Earth's surface
So the weight of the astronaut is

(b) 21.1 N
The spacecraft is located at a distance of

from the center of Earth.
The acceleration due to gravity at a generic distance r from the Earth's center is

where G is the gravitational constant and M is the Earth's mass.
We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:
(1)
the acceleration due to gravity at r=6R instead will be

And substituting (1) into this formula,

So the weight of the astronaut at the spacecratf location is

Answer:
Answer:B
Explanation:
Because it all stayed consistant
The impulse (the variation of momentum of the ball) is related to the force applied by

where

is the variation of momentum, F is the intensity of the force and

is the time of application of the force.
Using F=1000 N and

, we can find the variation of momentum:

This

can be rewritten as

where

and

are the final and initial momentum. But the ball is initially at rest, so the initial momentum is zero, and

from which we find the final velocity of the ball: