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shtirl [24]
3 years ago
11

A wire carries a 2a current. what is the current in a second wire that delivers twice as much charge in the same amount of time?

Physics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

4A

Explanation:

Current is charge per time.  So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.

2 × 2A = 4A

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Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massle
Alik [6]

Answer:

The value of mass 1, m1= 6/5m

The value of mass 2, m2= 3/5m

Explanation:

case 1:

here tension and the acceleration will be:

for m1;

  • mg-T=ma
  • 2mg - 2T = 2ma  .....1.

for m2:

  • 2T-mg = ma/2 ..... 2.

adding the both equations,

2mg - 2T + 2T-mg = 2ma + ma/2

a = 2/5 g

putting the value of a into the equation 1.

mg - T = m* (2/5)g

T = 3/5 ( mg )

now

case 2:

The two identical blocks are released from the rest, the tension remains the same as the case 1.

so,

for m1:

  • 2T-m2g=0

for m2:

  • 2m2g - 2T =0

adding both equations we get,

2T-m2g + 2m2g - 2T = 0

m2 = m1 / 2

T = m1*g / 2

here we know that

T (case1) = T (case2)

3/5 ( mg ) = m1*g / 2

m1 = 6/5 m

hence

m2 = 3/5 m

learn more about tension here:

<u>brainly.com/question/23590078</u>

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4 0
2 years ago
A small increase in aperture will result in
Nat2105 [25]

A small increase in aperture will result in a small increase in brightness.

8 0
3 years ago
Read 2 more answers
What is the technical name for the animal kingdom
enyata [817]
The community off animals
6 0
3 years ago
A cannon fires a shell straight upward; 1.7 s after it is launched, the shell is moving upward with a speed of 17 m/s. Assuming
Alex787 [66]

Answer:

a) 0.323m/s b) 54.278 m/s

Explanation:

The shell is moving upward with a speed of 17m/s

1.7s after it was launch

Using equation of motion on a straight line,

Vfinal = Vintial + acceleration due to gravity *time

Where V represent the speed(velocity)

Vinital = V(at 1.7s) - 9.81* 1.7

Vinital = 17 - 16.677

a) Vinital = 0.323m/s

b) using the same equation,

V(after 5.5s) = Vinital + 9.81*5.5s

Vafter5.5s = 0.323 + 53.955

V after 5.5s = 54.278m/s

4 0
3 years ago
Your pencil is 11 cm long . How long is it in millimeters?
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It is 110 millimetres. =)
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