Answer:
t_pass = 2.34 m
t_stop = 4.68 s
Thus, for the car passing at constant speed the pedestrian will have to wait less.
Explanation:
If the car is moving with constant speed, then the time taken by it will be given as:
where,
t_pass = time taken = ?
D = Distance covered = 23 m
v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s
Therefore,
<u>t_pass = 2.34 m</u>
<u></u>
Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:
Now, for the passing time we use first equation of motion:
<u>t_stop = 4.68 s</u>
In order to lift the load "L" by "X" meters, the effort "E" needs to travel the distance of 2X meters. (The entire rope needs to be pulled by "E" for a distance of 2X.) Since it is a ratio. it has no units of measurement.
Answer:
it means the altitude of the object is 5m high or wide
Answer:
the height above the ground through Mr. Voytko lifted the apple is 2.5 m.
Explanation:
Given;
energy of Mr. Voytko, E = 7.35 J
mass of the apple, m = 0.3 kg
Apply the principle of conservation of energy.
Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.
E = mgh
where;
h is the height above the ground through Mr. Voytko lifted the apple.
g is acceleration due to gravity = 9.8 m/s²
h = E / (mg)
h = 7.35 / (0.3 x 9.8)
h = 2.5 m
Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.