Given:
speed of passing pony 5 m/s
frequency of the sound produced: 221 Hz
speed of sound 342 m/s
Let us use the Doppler Shift Formula:
Where the <span>source is moving away from the observer at rest
</span>
f' = (v / v+vs) f
Where, vs<span> = Velocity of the Source,</span>
v = Velocity of sound or light in medium,
f = Real frequency,
f' = Apparent frequency.
f'= [342 m/s / (342 m/s+5m/s)] * 221 Hz
f' = 0.9856 * 221Hz
f' = 217.8176 Hz or 218 Hz
The observed frequency <span>of the hooves after the pony has passed your position is 218 Hz.</span>
Drag is usually ignored because its effect on the horizontal velocity is usually negligible due to the short time of flight.
An object's surface area and geometry, along with the object's surrounding wind speed will affect the drag force.
In most cases, drag force will cause the object to land horizontally closer to the predicted landing point as drag is a resistive force.
Explanation:
the impact cull ball stop,bit transfer all of it
momentum and kinetic energy to the another ball resunting in the hit ball rolling with the initial speed of the cue ball .
De-celleration because speed is lower as time goes on
To solve this problem we will apply the concepts related to Newton's second law for which the product of mass and acceleration is defined as the force applied to an object. Mathematically this is,

Here,
Net external Force
m = Mass of the body
a = Acceleration
The net force on the body would be given by the difference between the ascending force and the weight, therefore,

Here,
F = Upward Force
W = Weight
The Weight is,


Then the
is


Finally replacing at the first equation we have,


Therefore the acceleration of the stone is 