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tensa zangetsu [6.8K]
2 years ago
8

The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be

Physics
1 answer:
eimsori [14]2 years ago
6 0

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

  • 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
  • 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

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Final velocity, v_f=50 m/s

The duration of collision, dt= 8.0 \times 10^{-3} s

Force, F = \frac{0.15 kg (50-(-40) m/s)}{8.0 \times 10^{-3} s}=1687.5 N

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A mother and daughter are on a seesaw in the park. How far from the center must the 160.9lb mother sit in order to balance the 6
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Answer:

The mother has to sit 2.17 ft from the center on the other side of the seesaw.

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we need that the absolute value of the torque exerted by the mom (160.9 lb) to be the same in magnitude (and of course opposite direction). So we assume that "d" is the distance at which the mother locates to make this torque equal in magnitude to her daughter's torque:

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3 years ago
A 0.15-kg ball is thrown into the air and rises to a height of 20.0 m. How much kinetic energy did the ball initially have?
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IF the toss was straight upward, then the kinetic energy it got
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