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2 years ago

The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be

1 answer:

6 0

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

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Second rule
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Fourth rule
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2 years ago

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An electron is accelerated by a 3.6 kv potential difference. the charge on an electron is 1.60218 × 10−19 c and its mass is 9.10

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As the power energy is converted into kinetic energy, we have then:
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Equating equations:
qV = mv ^ 2/2
From here, we clear the speed:
v = root (2qV / m)
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Fc = Fm
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By clearing the magnetic field we have:
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