Answer:
True.
Explanation:
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
Simply stated, a vector quantity has both magnitude and direction.
Thus, a vector quantity is: A deer running 15 meters per second due west.
Answer: F = 0.17N
Explanation: From the Newton second law of motion.
F= m(v-u)/t.
V=180km/hr = 180×1000/3600= 50m/s
U= 160km/hr = 160×1000/3600= 44.44m/s
t= 5secs
F=m(v-u)/t
F= 0.150(50-44.44)/5
F=0.150×5.56/5
F= 0.835/5
F= 0.17N rounded to two decimal places.
The velocity of the combined mass after the collision is 0.84 ms-1.
<u>Explanation:</u>
According to law of conservation of momentum, the change in momentum before collision will be equal to the change in momentum of the objects after collision in isolated system.
But as it is perfectly inelastic collision in the present case, the final momentum will be based on the product of total mass of both the object with the velocity with which the collision occurred. This form is attained from the law of conservation of momentum as shown below:
So as law of conservation of momentum,
Here = 3 kg and = 2 kg are the masses of objects 1 and 2, = 1.4 m/s and = 0 are the initial velocities of object 1 and object 2, and are the final velocities of the objects.
So after collision, object 1 get sticked to object 2 and move together with equal velocity = = . Thus the above equation will become,
So the final velocity is
Thus,
= 0.84 ms-1.
Explanation:
I have a lot to say it was very nice to meet my parents are u doing well I dont want too its been so much I love you so I was like u know I am not a man but you are the auditions I have been in a long long long life is a triangle and a chair for me and my parents think about the way I
Answer:
d) 700 m/s
Explanation:
if k is the force constant and x is the maximum compression distance, then:
the potential energy the spring can acquire is given by:
U = 1/2×k×(x^2)
and, the kinetic energy system is given by:
K = 1/2×m×(v^2)
if Ki is the initial kinetic energy of the system, Ui is the initial kinetic energy of the system and Kf and Uf are final kinetic and potential energy respectively then, According to energy conservation:
initial energy = final energy
Ki +Ui = Kf +Uf
Ui = 0 J and Kf = 0J
Ki = Uf
1/2×m×(v^2) = 1/2×k×(x^2)
m×(v^2) = k×(x^2)
v^2 = k×(x^2)/m
= (500)×((21×10^-2)^2)/(19×10^-3 + 8)
= 2.75
v = 1.66 m/s
the v is the final velocity of the bullet block system, if m1 is the mass of bullet and M is the mass of the block and v1 is the initial velocity of the bullet while V is the initial velocity of the block, then by conservation linear momentum:
m1×v1 + M×V = v×(m1 + M) but V = 0 because the block is stationary, initially.
m1×v1 = v×(m1 + M)
v1 = v×(m + M)/(m1)
= (1.66)×(19×10^-3 + 8)/(19×10^-3)
= 699.86 m/s
≈ 700 m/s
Therefore, the velocity of the bullet just before it hits the block is 700 m/s.