Answer:
0.321659377 m/s²
1.383138458 m/s
0.321659377 m/s²
0.62667 m/s²
0.7044 m/s² and 27.17°
Explanation:
d = Diameter of rim = 13 in = 
r = Radius = 
= Final angular velocity = 
= Initial angular velocity = 0
= Angular acceleration
t = Time taken = 4.3 s
Equation of rotational motion
Tangential acceleration is given by
The tangential acceleration of the bug is 0.321659377 m/s²
Tangential velocity is given by
The tangential velocity of the bug is 1.383138458 m/s
The tangential acceleration is constant which is 0.321659377 m/s²
Centripetal acceleration is given by
The centripetal acceleration of the bug is 0.62667 m/s²
The resultant of the acceleration gives us total acceleration
Direction is given by
The magnitude and direction of the acceleration is 0.7044 m/s² and 27.17°
Considering the Coulomb's Law, the magnitude of the Coulomb force is 3.1865 N.
<h3>Coulomb's Law</h3>
Charged bodies experience a force of attraction or repulsion on approach.
From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.
From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
where:
- F is the electrical force of attraction or repulsion. It is measured in Newtons (N).
- Q and q are the values of the two point charges. They are measured in Coulombs (C).
- d is the value of the distance that separates them. It is measured in meters (m).
- K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹
.
The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
<h3>This case</h3>
In this case, you know that:
- The two uncharged sphere are separated by the distance of d= 3.50 m
- The number of electrons are 1.30×10¹².
- Electrons is elementary charge and charges on both the sphere is same. The value of electron is 1.602×10⁻¹⁹ C. This is, Q=q=1.30×10¹²×1.602×10⁻¹⁹ C= 2.0826×10⁻⁷ C
Replacing in Coulomb's Law:
Solving:
<u><em>F= 3.1865 N</em></u>
Finally, the magnitude of the Coulomb force is 3.1865 N.
Learn more about Coulomb's Law:
brainly.com/question/26892767
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Answer:
b. 1.1 m
Explanation:
It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,
where,
s₁ = distance of fulcrum from left mass
s₂ = distance of fulcrum from right mass
In order to achieve balance, the torque due to both masses must be equal:
s₁ = 1.1 m
Hence, the correct option is:
<u>b. 1.1 m</u>
It has to be D because the arrow will drop as it moves, if it were a gun, you'd lead the target so fire below it, but due to it being an arrow, you aim high not low. Also, they didnt specify how fast anything is, so you'd probably miss if you actually did it.
