the balanced chemical equation for the reaction is as follows
H₃PO₄ + 3KOH ---> K₃PO₄ + 3H₂O
stoichiometry of H₃PO₄ to KOH is 1:3
first we have to find which the limiiting reactant is
as the amount of product formed depends on the amount of limiting reactant present
number of H₃PO₄ moles reacted - 4.4 mol
if H₃PO₄ is the limiting reactant
1 mol of H₃PO₄ reacts with 3 mol of KOH
then 4.4 mol of H₃PO₄ reacts with - 3 x 4.4 mol = 13.2 mol of KOH
but only 3.8 mol of KOH is present
therefore KOH is the limiting reactant
stoichiometry of KOH to K₃PO₄ is 3:1
number of KOH moles reacted - 3.8 mol
therefore number of K₃PO₄ formed = number of KOH moles reacted / 3
= 3.8 mol / 3 = 1.3 mol
answer is 1.3 mol of K₃PO₄
