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Amiraneli [1.4K]
4 years ago
8

25. Compare the compositions of binary ionic and binary molecular compounds. 26. Write the general chemical formula for an acid,

and discuss what each component of the formula represents.
Chemistry
2 answers:
QveST [7]4 years ago
7 0
Ionic binary compounds -- hold a metal cation and an anion made of a nonmetal anion. Example: calcium phosphate: Ca = 2+ (Group IIA) PO4 = 3- (phosphate) the lowest shared multiple of 2+ and 3- is 6. You must have 3 Ca2+ to make +6; you must have 2 PO43- to make -6. The sum of the positive and negative charges must be equivalent in a compound for the reason that they are electrically neutral. Ca3(PO4)2 -- calcium phosphate 

Binary molecular compounds -- has two or more nonmetals fused covalently. There are no ions current for the reason that the atoms share electrons. Prefixes are used to designate the number of atoms of each kind present. Example: SO2 -- sulfur dioxide  

The overall formula for an acid is HX, where X is an anion. Binary acids cover H and a nonmetal and are called with the prefix "hydro" and the suffix "ic".
Murljashka [212]4 years ago
5 0

Explanation:

25. Binary ionic compounds: They are known as the compounds which contains a cation formed from a metal and an anion formed from a non-metal or a polyatomic anion. For example : Barium sulfate

Ba : +2 ( metal of group II-A)

SO_4 : -2 ( sulfate)

These two ions combine to form a binary ionic compound having formula BaSO_4

Binary Molecular compounds: They are known as the compounds which contain two or more non-metals that are bonded covalently. In these compounds, no ions are present because the electrons are shared by the atoms. Examples are: PCl_3 : phosphorous trichloride

SO_2 : sulfur dioxide

26. The general chemical formula for an acid is HX where H is the hydrogen and X is the non-metal or polyatomic ions. Examples of acids are:

HF : Hydrofluoric acid

H_2SO_4 : Sulfuric acid

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1826.5g of methanol (CH3OH), molar mass = 32.0 g/mol is added to 735 g of water, what is the molality of the methane 0.0348 m 1.
Snowcat [4.5K]

Answer:

Molality = 1.13 m

Explanation:

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of CH_3OH = 26.5 g

Molar mass of CH_3OH = 32.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{26.5\ g}{32.04\ g/mol}

Moles\ of\ CH_3OH= 0.8271\ moles

Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )

So, molality is:

m=\frac {0.8271\ moles}{0.735\ kg}

<u>Molality = 1.13 m</u>

4 0
3 years ago
A gas that exerts a pressure of 15.6 psi in a container with the volume of ______ L will exert a pressure of 24.43 psi when tran
dybincka [34]
Boyle's Law states: pV = constant.

24.43 x 1.895 = 46.29485

therefore, 15.6 x _____ = 46.29485

unknown = 2.968L
4 0
3 years ago
Read 2 more answers
The enthalpy of reaction changes somewhat with temperature. Suppose we wish to calculate ΔH for a reaction at a temperature T th
Contact [7]

Answer:

-99.8 kJ

Explanation:

We are given the methodology to answer this question, which is basically  Kirchhoff law . We just need to find the heats of formation for the reactants and products and perform the calculations.

The standard heat of reaction is

ΔrHº = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where ν are the stoichiometric coefficients in the balanced equation, and ΔfHº are the heats of formation at their  standard states.

  Compound                 ΔfHº (kJmol⁻¹)

        SO₂                             -296.8

         O₂                                    0

         SO₃                            -395.8

The balanced chemical equation is

SO₂(g) + ½O₂(g) → SO₃(g)

Thus

Δr, 298K Hº( kJmol⁻¹ ) =  1 x (-395.8) - 1 x (-296.8) = -99.0 kJmol⁻¹

Now the heat capacity of reaction  will be be given in a similar fashion:

Cp rxn = ∑ ν x Cp of products - ∑ ν x Cp of reactants

where ν is as above the stoichiometric coefficient in the balanced chemical equation.

Cprxn ( JK⁻¹mol⁻¹) = 50.7 - ( 39.9 + 1/2 x 29.4 ) = - 3.90

                         = -3.90 JK⁻¹mol⁻¹

Finally Δr,500 K Hº = Δr, 298K Hº +  CprxnΔT

Δr,500 K Hº = - 99 x 10³ J + (-3.90) JK⁻¹ ( 500 - 298 ) K = -99,787.8

                     = -99,787.8 J x 1 kJ/1000 J  = -99.8 kJ

Notice thie difference is relatively small that is why in some problems it is o.k to assume the change in enthalpy is constant over a temperature range, especially if it is a small range of temperatures.

3 0
3 years ago
Before using any chemical in the lab, Way should One first read the material safety data sheet?
Talja [164]
You read the SDS so you know what the hazards are working with the chemicals in the experiment and what precautionary measures should be taken. You wouldn't want to spill sensitizer or corrosive chemicals all over your hands or breath in carcinogens or chemicals that effect the central nervous system. The SDS will tell you what personal protective equipment you should use like the type of gloves, or whether or not you should work in a fume hood.
8 0
3 years ago
Find the magnetic force experienced by a proton moving with the speed of 3 × 105 m/s in the magnetic field B of magnitude 6 × 10
Karo-lina-s [1.5K]

The magnetic force experienced by a proton moving with a speed of 3 ×10^{5} m/s in the magnetic field B of magnitude 6 ×10^{-5} T will be 2.88×10^{-18} N.

Magnetic force can be defined as the attraction or repulsion force that arises between electrically charged particles due to the motion of the charged particles.

Given,

Speed = 3×10^{5} m/s

Magnetic Field, B= 6 ×10^{-5} T

Magnetic force is the product of velocity, the charge of a proton, and the magnetic field present there.

The magnetic force can be represented as:

F=qvB

F=1.6×10^{-19}×3×10^{5} ×6 ×10^{-5}

F=2.88×10^{-18} N

Hence, the magnetic force experienced by the proton will be 2.88×10^{-18} N.

Learn more about Magnetic force here:

brainly.com/question/25932320

#SPJ10

6 0
2 years ago
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