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jenyasd209 [6]
2 years ago
8

What is the answer to question 7, NH4C2H3O2

Chemistry
2 answers:
Veronika [31]2 years ago
7 0

Answer:

Ammonium acetate was not sure at first but it was Ammonium acetate sorry i was confused at first

Hope this helps :D

Sliva [168]2 years ago
4 0
The answer is Ammonium acetate
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Part A

Explain how each of the following concepts applies to Dr. Khan’s research.

Survey

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Big Five theory of personality

Part B

Explain the limitations of Dr. Khan’s study based on the research method used.

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Use the graph to answer the following questions.

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5 0
3 years ago
Read 2 more answers
Write the ions present in a solution of na3po4. express your answers as chemical formulas separated by a comma. offset subscript
dexar [7]
Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:

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5 0
3 years ago
When the pressure that a gas exerts on a sealed container changes from 22.5 psi to ? psi, the temperature changes from 110 degre
natta225 [31]
Using Gay-Lussac's Law, pressure is proportional to (absolute) temperature in Kelvin. We first convert the temperature values to Kelvin: 110 C = 383.15 K, while 65 C = 338.15 K.
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8 0
3 years ago
Which of the following is not a clue that a chemical reaction has taken place? *
DaniilM [7]

Answer:

A pure solid is heated and turns into a pure liquid.

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No colour change recorded, only change of state, hence this is a physical change - physical changes I.e. change of state and temperature are not chemical reactions.

7 0
2 years ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

3 0
3 years ago
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