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Bogdan [553]
3 years ago
5

A sample of Manganese (II) chloride has a mass of 19.8 grams before heating, and 12.6 grams after heating until all the water is

driven out. Based on this information, how many water molecules were attached to each molecule of Manganese (II) chloride
Chemistry
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

no. of water molecules associated to each molecule of MnCl_2 = 4

Explanation:

Mass of MnCl_2 before heating = 19.8 g

Mass of MnCl_2 after heating = 12.6 g

Difference in mass of MnCl_2 before and after heating

                                 = 19.8 - 12.6 = 7.2 g

Difference in mass corresponds to mass of water driven out.

Molar mass of water = 18 g/mol

No. of moles of water = \frac{7.2}{18} = 0.4\ mol

Mass of MnCl_2 obtained after heating is mass of anhydrous MnCl_2.

Mass of anhydrous MnCl_2 = 12.6 g

Molar mass of MnCl_2 = 125.9 g/mol

No. of mol of anhydrous MnCl_2 = \frac{125.9}{125.9} = 0.1\ mol

so,

0.1 mol of MnCl_2 have 0.4 mol of water

1 mol of MnCl_2 will have = \frac{0.4}{0.1} =4\ mol

Hence, no. of water molecules associated to each molecule of MnCl_2 = 4

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