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d1i1m1o1n [39]
2 years ago
13

A teacher carried out a class demonstration on

Chemistry
1 answer:
goldenfox [79]2 years ago
4 0

One of the hydrogens in the NH3 is replaced in the first reaction by the methyl group, or -CH3. The NH3 can have more than one H substituted for it, therefore the final product frequently comprises a blend of methylamine, dimethylamine, and trimethylamine.

A halogenoalkane and ethanolic ammonia can be used in a nucleophilic substitution process to produce primary aliphatic amines like methylamine (CH3NH2).

NH3 + CH3Cl = HCl + CH3NH2

The process is challenging because any unreacted ammonia can react with the generated HCl:

NH3+HCl yields NH4Cl.

Since the N in CH3NH2 still has a single pair of electrons, it can act as a base and interact with the HCl that is created in one of the following ways:

CH3NH2+HCl becomes CH3NH3+Cl.

or as a nucleophile and react with any chloromethane that hasn't been reacted:

(CH3)2NH + HCl = CH3NH2 + CH3Cl

Learn more about nucleophilic substitution here-

brainly.com/question/28325919

#SPJ9

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Given the following equation: 2K + Cl2 -> 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

  Complete equation of the reaction:

              2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

Calculating number of moles of K

      Number of moles = \frac{mass}{molar mass}

        Number of moles of K =  \frac{4}{39} = 0.103mol

From the given reaction equation:

   2 moles of K will produce 2 moles of KCl

 Therefore 0.103mol of K will produce 0.103mol of KCl

To find the mass of KCl produced,

   Mass of KCl = number of moles of KCl x molar mass

Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹

Mass of KCl = 0.103 x 74.5 = 42.65g

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