Answer:
Half Cell (1)oxidation reaction (2) redox reaction
Anode----(1)and(2) electrochemical cell at which oxidation occurs
Cathode---(1)and(2)electrochemical cell at which reduction
Electrolytes----(1)ammonium chloride------
Oxidation Reaction --- (1)in Anode(2)in Anode
Reduction Reaction----(1)in Cathode(2)in cathode
Bridge---(1)Zinc–carbon battery(2) Galvanic cell
Relative size ------ (1)smaller--------(2)much larger
Explanation:
Answer:
The element is Rubidium . The ion only loss one electron to make the electron 36 . But the proton number(atomic number) is 37. The chemical compound should RbBr
X = Rubidium(Rb)
Explanation:
The ion of element X has a mass number of 85 and electron of 36. An elements is charge if it either loss or receive electron. Base on the charge the ion has loss electron. Bromine usually possess a negatively charge ion. That makes the X electron a positively charge ion.
proton number = Atomic number
Proton number = electron number when not charged
Mass number = proton number + neutron number
Proton is usually same number with the electron to make the element neutral. But when the atom is charge the atom usually loss or gain electron.
In this case, the atom X loss one electron thereby reducing the electron number to 36 . Recall, the electron is equal to proton only if the atom is uncharged. This means the proton number should be 37 as one electron was loss.
Element with proton number(atomic number) of 37 is rubidium. It is an alkali metal that is very reactive.
Answer:
The concentration of the standard NaOH solution is 0.094 moles/L.
Explanation:
In the titration, the equivalence point is defined as the point where the moles of NaOH (the titrant) and KHP (the analyte) are equal:
moles of NaOH = moles of KHP
![[NaOH]xV_{NaOH} = moles of KHP](https://tex.z-dn.net/?f=%5BNaOH%5DxV_%7BNaOH%7D%20%3D%20moles%20of%20KHP)
![[NaOH] = \frac{moles of KHP}{V_{NaOH}}](https://tex.z-dn.net/?f=%5BNaOH%5D%20%3D%20%5Cfrac%7Bmoles%20of%20KHP%7D%7BV_%7BNaOH%7D%7D)
The 
is 40.82mL = 0.04082L and the moles of KHP are
Replacing at the first equation:
![[NaOH] = \frac{3.827x10^{-3}moles}{0.04082L} = 0.094 moles/L](https://tex.z-dn.net/?f=%5BNaOH%5D%20%3D%20%5Cfrac%7B3.827x10%5E%7B-3%7Dmoles%7D%7B0.04082L%7D%20%3D%200.094%20moles%2FL)
