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2 years ago

Complete the graphic organizer. Basic Parts of an Atom

Chemistry

1 answer:

maxonik [38]2 years ago

5 0

Answer:

I'm not sure but I think the answer is electrons, protons and neutrons.

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Which of the following shows the 3 main jobs of a cell?

skad [1K]

C is the answer hope this helps

8 0

2 years ago

Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

2 years ago

Metric dimensional analysis worksheet problem: 645 kg to g

Andrews [41]

Answer:

645000 grams my dude

3 0

2 years ago

NO GUESSING!ONLY RIGHT ANSWER

lutik1710 [3]

<h3> <u>ANSWER</u></h3>

2. Neon, only

<h3><u>EXPLANATION</u></h3>

When Na and F combine they form an electron configuration of 2-8. Na electron configuration is 2-8-1 while F is 2-7, so when they form an ionic bond F will gain Na outermost electron to complete its valence shell due to having a higher negativity. Neon has an electron configuration of 2-8 but argon has 2-8-8.

7 0

2 years ago

An element has three different isotopes. One has a mass of 35.00 amu; another has a mass of 36.00 amu; and another has a mass of

yulyashka [42]

Answer:

so 35+38+36÷3= 109÷3 =36.33 AMU

8 0

2 years ago