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attashe74 [19]
3 years ago
12

a collection of nerve fibers through which impulses travel between the central nervous system and other parts of the body

Chemistry
1 answer:
rewona [7]3 years ago
4 0
A collection of nerve fibers through which impulses travel between the central nervous system and other parts of the body are the nerves.
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The pH of a solution prepared by the addition of 100mL 0.002M HCL to 100mL distilled water is closest to:
IRISSAK [1]

Answer:

d.3.0

Explanation:

Step 1: Calculate the final volume of the solution

The final volume is equal to the sum of the volumes of the initial HCl solution and the volume of distilled water.

V₂ = 100 mL + 100 mL = 200 mL

Step 2: Calculate the final concentration of HCl

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂ = 0.002 M × 100 mL/200 mL = 0.001 M

Step 3: Calculate the pH of the final HCl solution

Since HCl is a strong acid, [H⁺] = HCl. We will use the definition of pH.

pH = -log [H⁺] = -log 0.001 = 3

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3 years ago
Which is not a property of a pure substance?
mr Goodwill [35]

varying composition is not a property of a pure substance

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Can someone help with this please? My teacher isnt responding to any of mine or my classmates requests for help
sergiy2304 [10]

Answer:

CO2 consists of individual molecules with one central carbon atom double bonded to two oxygen atoms. Silicon does not form double bonds with oxygen. CO2 is gas but SiO2 is a solid because SiO2 has a giant molecular structure. CO2 has a simple molecular structure, and because of this, CO2 is gas but SiO2 is solid at room temperature.

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Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
aliya0001 [1]

Answer:

Explanation:1. NaNH2 (1-Butene)

CH3CH2CH2CH2Cl --------------> CH3CH2CH=CH2 + HCl (elimination reaction)

2. Br2, CCl4

CH3CH2CH=CH2 ---------------> CH3CH2CH(Br)CH2Br (Simple addition Reaction)

3. NaNH2 (1-Butyne)

CH3CH2CH(Br)CH2Br ----------------> CH3CH2C≡CH + 2HBr

Sodamide (NaNH2) is a very strong base and generally results in Terminal Alkynes when treated with Vicinal Dihalides.

Alcoholic KOH on the other hand results in the formation of Alkynes with triple bonds in the middle of the molecule.

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3 years ago
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