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Luda [366]
3 years ago
5

Write the rate laws for the following elementary reactions. (a) ch3nc(g) → ch3cn(g)

Chemistry
1 answer:
klasskru [66]3 years ago
4 0

Answer:

a. rate = k[CH3NC]

Explanation:

In elementary reactions you use the coefficients of the reactants for the exponents. Other than that its the same. In this elementary step, the coefficients of the reactant is 1.  

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Na+ FeBr2 what are the products
densk [106]

Hello:


Balanced equation:


2 Na + FeBr2 = 2 NaBr + Fe


Reaction type: single replacement


Hope that helps!

8 0
4 years ago
What do scientists Need to know about a compound in order to Classify it
OleMash [197]
Compounds are classified according to the elements that make them up. For example, oxides contain one or more oxygen atoms, hydrides contain one or more hydrogen atoms.
compounds form different types of bonds too. a metal and nonmetal element will create an ionic bond, two nonmetal elements create covalent bonds
6 0
3 years ago
Which reason best explains why metals are malleable?
sleet_krkn [62]

Answer:

A

Explanation:

because they have delocalized electrons

5 0
3 years ago
Assuming the metals lose all their valence electrons and the nonmetals gain electrons to complete the s-p subshells, which listi
Nataly [62]

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}. When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.

Na^{+} : 1s^{2}2s^{2}2p^{6}

Atomic number of fluorine is 9 and its electronic configuration is 1s^{2}2s^{2}2p^{5}. When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.

F^{-} : 1s^{2}2s^{2}2p^{6}

Atomic number of aluminium is 13 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.

Al^{3+} : 1s^{2}2s^{2}2p^{6}

Thus, we can conclude that the listing for aluminum is correct.

8 0
3 years ago
For the following reaction, 5.05 grams of copper are mixed with excess silver nitrate. The reaction yields 11.0 grams of copper(
andreyandreev [35.5K]

Answer:

14.9 g is the ideal yield of Cu(NO₃)₂

Explanation:

Reactants for the reaction: Cu and AgNO₃

Products: Copper nitrate and Ag

The balanced reaction is: Cu(s) + 2AgNO₃(aq) →  2Ag (s) + Cu(NO₃)₂

As the silver nitrate is in excess, the Cu will be the limiting reagent.

We convert the mass to moles → 5.05 g . 1 mol/ 63.55 g = 0.0794 moles

Ratio is 1:1, so 0.0794 moles will produce 0.0794 moles of Cupper(II) nitrate. We convert the moles to mass, and that value will be the theoretical yield.

0.0794 mol . 187.55 g /1 mol =  of Cu(NO₃)₂

8 0
3 years ago
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