Answer:
And we have to calculate the number of moles of sucrose present in a lb mass of sucrose: Moles of sucrose=454⋅g342.30⋅g⋅mol−1=1.33⋅mol .
Explanation:
<u>Brainliest</u><u> </u><u>Answer </u><u>Pls</u>
1,38×10²² = 0,138×10²³
0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol
It's ZINC (Zn)
:•)
Answer: 2NH4Br(aq)+Pb(C2H302(aq)-------------------->
2NH4C2H3o2(aq) + PbBr2(s)
Explanation:
The net equation is :Pb2+ (aq)2Br (aq)---------------------->PbBr2(s)
the spectator ions NH4 +C2H3O2 are canceled