The natural abundance of 2h is 0.015% and that of 18o is 0.20%. How many 2h218o molecules are there in 1.0 moles of water?
1 answer:
Answer:
Explanation:
Probability of one ²H is 0.00015 = 1.5× 10⁻⁴
Probability of two ²H is 1.5× 10⁻⁴ × 1.5 × 10⁻⁴ = 2.25 × 10⁻⁸
Probability of two ²H plus one ¹⁸O is 2.25 × 10⁻⁸ × 0.0020
= 4.5× 10⁻¹¹
Molecules in 1.0 mol water = 1.0 × 6.022 × 10²³ × 4.5 × 10¹¹
= 2.7 × 10¹³
There are 2.7 × 10¹³ molecules of ²H₂¹⁸O in 1.0 mol of water.
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Answer : The mass of combustion products formed are 134 lbs.
Explanation :
The balanced chemical reaction will be:
Given :
Mass of = 29 lbs = 13154.2 g
conversion used : 1 lbs = 453.592 g
Molar mass of = 44 g/mole
First we have to calculate the moles of .
Now we have to calculate the moles of and
.
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 3 moles of
So, 298.9 mole of react to give
moles of
and,
As, 1 mole of react to give 4 moles of
So, 298.9 mole of react to give
moles of
Now we have to calculate the mass of and
.
Molar mass of = 44 g/mole
Molar mass of = 18 g/mole
and,
The total mass of products = Mass of + Mass of
The total mass of products = 86.98 + 47.44 = 134.42 ≈ 134 lbs
Therefore, the mass of combustion products formed are 134 lbs.