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3 years ago

In the triangle below, what ratio is sin θ?

Mathematics

2 answers:

leonid [27]3 years ago

8 0

Answer: The required ratio is $\dfrac{12}{13}.$

Step-by-step explanation: In the given triangle, we are to find the ratio of sinθ.

We know that

in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.

For the given right-angled triangle, we get

$\sin\theta=\dfrac{perpendicular}{hypotenuse}\\\\\\\Rightarrow \sin\theta=\dfrac{36}{39}\\\\\\\Rightarrow \sin\theta=\dfrac{12}{13}.$

Thus, the required ratio is $\dfrac{12}{13}.$

hodyreva [135]3 years ago

3 0

Bringing to mind SOHCAHTOA, we remember that the sine is the opposite divided by the hypotenuse.
Thus, our answer is $\frac{36}{39}=\boxed{\frac{12}{13}}$ .

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slamgirl [31]

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2 years ago

The lines y=x+1 and y=-x-3 are graphed. What is the solution to the system? Please help

Fed [463]

Answer: (-2, -1)

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be very careful with your signs.

Let's just do a quick review on the coordinate system. On the x-axis, left means negative and right means positive and on the y-axis, down means negative and up means positive.

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3 years ago

The probability of drawing a pearl bead out of a bag of mixed beads is 2/3. What is the probability of drawing a bead which is n

Georgia [21]

Answer:

$\frac{1}{3}$ probability of drawing a bead which is not a pearl

Step-by-step explanation:

For each bead that you draw, there are only two possible outcomes. Either it is a pearl bead, or it is not. The sum of these probabilities = 100% = 1.

2/3 probability of drawing a pearl bead.

p probability of drawing a non pearl bead.

What is the probability of drawing a bead which is not a pearl?

$p + \frac{2}{3} = 1$