Question

In the triangle below, what ratio is sin θ?

Answer 1

Answer:  The required ratio is $\dfrac{12}{13}.$

Step-by-step explanation:  In the given triangle, we are to find the ratio of sinθ.

We know that

in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.

For the given right-angled triangle, we get

$\sin\theta=\dfrac{perpendicular}{hypotenuse}\\\\\\\Rightarrow \sin\theta=\dfrac{36}{39}\\\\\\\Rightarrow \sin\theta=\dfrac{12}{13}.$

Thus, the required ratio is $\dfrac{12}{13}.$

Answer 2

Bringing to mind SOHCAHTOA, we remember that the sine is the opposite divided by the hypotenuse.
Thus, our answer is $\frac{36}{39}=\boxed{\frac{12}{13}}$.