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Ostrovityanka [42]
3 years ago
6

In the triangle below, what ratio is sin θ?

Mathematics
2 answers:
leonid [27]3 years ago
8 0

Answer:  The required ratio is \dfrac{12}{13}.

Step-by-step explanation:  In the given triangle, we are to find the ratio of sinθ.

We know that

in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.

For the given right-angled triangle, we get

\sin\theta=\dfrac{perpendicular}{hypotenuse}\\\\\\\Rightarrow \sin\theta=\dfrac{36}{39}\\\\\\\Rightarrow \sin\theta=\dfrac{12}{13}.

Thus, the required ratio is \dfrac{12}{13}.

hodyreva [135]3 years ago
3 0
Bringing to mind SOHCAHTOA, we remember that the sine is the opposite divided by the hypotenuse.
Thus, our answer is $\frac{36}{39}=\boxed{\frac{12}{13}}$.
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a) The proportions are not form matched-pairs data.

b) The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence of a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

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a) Two data sets are "paired" when the following one-to-one relationship exists between values in the two data sets:

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p_1=X_1/n_1=27/1456=0.0185

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p_2=X_2/n_2=41/2895=0.0142

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p_d=p_1-p_2=0.0185-0.0142=0.0044

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{27+41}{1456+2895}=\dfrac{68}{4351}=0.0156

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