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ipn [44]
3 years ago
12

A line that contains the point (2,-3) and has a slope of 8

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
6 0
Y=mx+b
Sub in what you know and solve
-3=8(2)+b
-3=16+b
-3-16=b
-19=b
The equation is y=8x-19
Hope this helps!
NeTakaya3 years ago
3 0
Y+3=8(x-3)
y=8x-27
hope this helps!
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Answer for brainliest
madam [21]

Answer:

c

Step-by-step explanation:

Negative 7 over 10 minus negative 2 over 10 = negative 5 over 10; therefore, the distance from A to B is absolute value of negative 5 over 10 equals 5 over 10 units.

the correct option is C.

(-7/10) - (-2/10)

then add -7/10 + 2/10 which will equal -5/10

6 0
3 years ago
The points in the table lie on a line. Find the slope of the line
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19. Calculate the size of the angle marked x in the diagram.
algol [13]

Answer:

151°

Step-by-step explanation:

126°+221°+95°+57°+70+x=720° ( sum of interior angles of hexagon)

x + 569° =720°

x = 720°- 569°

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7 0
3 years ago
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A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
Can someone plz help me
Illusion [34]
First rectangle:
Has 3 cubes in each 5 layers, and imagine it, so we have all dimension needed which is:
l=3 unit
w=1 unit
h=5 unit.
V=l×w×h
V=3×1×5
V=15 cubic inches.

Second rectangular:
Doing the same like that to get:
l=5 unit
w=1 unit
h=3 unit
V=15 cubic inches. As a result, there are no prism that are greater to each other, which mean that they have the same volume of 15 cubic inches. Hope it help!
6 0
3 years ago
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