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4 years ago

Which of the following statements is not true regarding physical properties and changes?

Chemistry

2 answers:

ratelena [41]4 years ago

8 0

I think it is B, but i am not sure

egoroff_w [7]4 years ago

8 0

Answer: Option (B) is the correct answer.

Explanation:

Physical properties and changes are defined as the property or changes that does not cause any change in the chemical composition of a substance.

For example, cutting a piece of sodium with knife is a physical change.

Whereas boiling point, density, melting point etc are all physical changes.

On the other hand, changes that bring change in chemical composition of a substance are known as chemical changes.

For example, reactivity, toxicity etc are all chemical changes.

Hence, we can conclude that the statement physical changes can change compounds into elements, is not true regarding physical properties and changes.

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Read 2 more answers

In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) H2O (g) CO2

jolli1 [7]

Answer: $K_{eq}$ at the temperature of the experiment is 0.56.

Explanation:

Moles of $CO$ = 0.35 mole

Moles of $H_2O$ = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of $CO$ = $\frac{0.35mol}{1.00L}=0.35M$

Initial concentration of $H_2O$ = $\frac{0.40mol}{1.00L}=0.40M$

Equilibrium concentration of $CO$ = $\frac{0.19mol}{1.00L}=0.19M$

The given balanced equilibrium reaction is,

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Initial conc. 0.35 M 0.40 M 0 M 0M

At eqm. conc. (0.35-x) M (0.40-x) M (x) M (x) M

Given: (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

$K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}$

Now put all the given values in this expression, we get :

$K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}$

$K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56$

Thus $K_{eq}$ at the temperature of the experiment is 0.56.

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3 years ago