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Nady [450]
3 years ago
13

An exothermic reaction

Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0

Answer:

An exothermic reaction  

✔ produces energy

.

In an endothermic reaction, the energy of the products is  

✔ more than

the energy of the reactants.

Activation energy is  

✔ always greater than

the potential energy of the products

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In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c
Darya [45]

Answer:

0.382g

Explanation:

Step 1: Write the reduction half-reaction

Al³⁺(aq) + 3 e⁻ ⇒ Al(s)

Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s

We will use the following relationships.

  • 1 A = 1 C/s
  • 1 mole of electrons has a charge of 96486 C (Faraday's constant)
  • 1 mole of Al is produced when 3 moles of electrons pass through the cell.
  • The molar mass of Al is 26.98 g/mol.

The mass of Al produced is:

41.0s \times \frac{100C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molAl}{3mole^{-} } \times \frac{26.98gAl}{1molAl} = 0.382gAl

7 0
3 years ago
What change in volume results if 50 mL of gas is cooled from 30 C to 4 C
11111nata11111 [884]

The relation between the volume of the gas and the temperature is established by Charles's law. With a decrease in the temperature, the volume decreases by 45.7 mL. Thus, option c is correct.

<h3>What is Charle's law?</h3>

Charle's law states the direct relation present between the temperature and the volume of the gas. The law is given as:

V₁ ÷ T₁ = V₂ ÷ T₂

Given,

V₁ = 50 mL

T₁ = 303.15 K

T₂ = 277.15 K

Substituting the value the final volume is calculated as:

50 ÷ 303.15 = V₂ ÷ 277.15

V₂ = (50 × 277.15) ÷ 303.15

= 45.71 mL

Therefore, option c. 45.7 mL is the final volume.

Learn more about Charles law here:

brainly.com/question/16927784

#SPJ1

5 0
2 years ago
Equation for questions 1-4:
Karolina [17]

Answer:

5.625 moles of oxygen, O₂.

Explanation:

The balanced equation for the reaction is given below:

4Al + 3O₂ —> 2Al₂O₃

From the balanced equation above,

4 moles of Al reacted with 3 moles of O₂.

Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:

From the balanced equation above,

4 moles of Al reacted with 3 moles of O₂.

Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.

Thus, 5.625 moles of O₂ is needed for the reaction.

3 0
3 years ago
How do you solve the level of a liquid in a graduated cylinder
Nezavi [6.7K]
Don’t really understand what you’re asking but, if you’re asking how to read a graduated cylinder:

Look at the graduated cylinder at eye level, find the meniscus, whatever the meniscus is at is your answer.
8 0
3 years ago
What purpose do each of the following play in the isolation and purification of ethyl 3- hydroxybutanoate?
Shalnov [3]

Explanation:

-Filter help — delete some big unreacted, undesirable species (norit is probably from what you are sorting through, its only carbon which cleans up things)

— extract with DCM because you are probably in an aqueous phase, and some butanoate is in it

- Anhydrous sodium absorbs excess of  water (dries the material)

-evaporation in the hood to clear the DCM and crystallize the product.

8 0
3 years ago
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