Let M = mass of the skier,
v2 = his speed at the end of the track.
By conservation of energy,
1/2 Mv^2 = 1/2 Mv2^2 + Mgh
Dividing by M,
1/2 v^2 = 1/2 v2^2 + gh
Multiplying by 2,
v^2 = v2^2 + 2gh
Or v2^2 = v^2 - 2gh
Or v2^2 = 4.8^2 - 2 * 9.8 * 0.46
Or v2^2 = 23.04 - 9.016
Or v2^2 = 14.024 m^2/s^2-----------------------------(1)
In projectile motion, launch speed = v2
and launch angle theta = 48 deg
Maximum height
H = v2^2 sin^2(theta)/(2g)
Substituting theta = 48 deg and value of v2^2 from (1),
H = 14.024 * sin^2(48 deg)/(2 * 9.8)
Or H = 14.024 * 0.7431^2/19.6
Or H = 14.024 * 0.5523/19.6
Or H = 0.395 m = 0.4 m after rounding off
Ans: 0.4 m
The answer in this question is 0.4 m
Answer:
True
Explanation:
This is a universal rule for all standard motor vehicles.
Answer: The velocity is 21.5m/s
Explanation:
Let's call:
M1 and V1 as the mass and velocity of the falcon:
M1 = 1.45kg
V1 = 26.5m/s
M2 and V2 as the mass and velocity of the dove:
M2 = 0.415kg
V2 = 4.35m/s
Where both velocities are positive because both animals move in the same direction.
We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:
V = (V1*M1 + V2*M2)/(M1 + M2)
V = (1.45kg*26.5m/s + 0.415kg*4.35m/s)/(1.45kg + 0.415kg) = 21.5m/s
Answer:
<em>1. c. Same in both</em>
<em>2. a. Case 1</em>
<em></em>
Explanation:
1. The balls are identical in all sense, which means that if they are dropped from the same height, they should posses the same kinetic energy just before they collide with either the concrete floor or the stretchy rubber. Also, since they reach the same height when they bounced of the concrete floor or the piece of stretchy rubber, it means that they posses the same amount of kinetic energy at this point. Since their kinetic energy at these two points are the same, and they have the same masses, then this means that their momenta at these two instances will also be equal. Since all these is true, then the change in the momentum of the balls between the instance just before hitting the concrete floor or the stretchy rubber material and the instant the ball just leave the floor or the stretchy material is the same for both.
2. The ball that falls on the concrete will experience the greatest force, since the time of impact is small, when compared to the time spent by the other ball in contact with the stretchy rubber material; which will stretch, thereby extending the time spent in contact between them.
From t=0 onwards I changes slowly and V changes abruptly across the inductor.
At time t=0, the voltage across the inductor equalises the battery voltage; nevertheless, Lenz's Law states that this induced EMF will always be opposed to the polarity of the battery. The voltage across the inductor is equivalent to the voltage of a battery because the inductor at time zero behaves like a second battery of the same voltage linked in reverse.
Because current can never be zero, voltage across the inductor decreases with time. If it did, there would be no back EMF to stop the current from flowing through the inductor because the magnetic field would not be changing. As a result, the inductor will become less of an open circuit as the current increases over time. The inductor will essentially behave like a resistor.
Learn more about inductor here:
brainly.com/question/15893850
#SPJ4
