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Scrat [10]
3 years ago
7

What is the seventh planet from the sun?

Physics
2 answers:
stiv31 [10]3 years ago
7 0

The seventh planet from the sun is Uranus.

soldier1979 [14.2K]3 years ago
5 0

Uranus I believe is the answer.

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A jogger runs 5.0 km on a straight trail at an angle of 60° south of west. What is the southern component of the run rounded to
mixer [17]

Given :

A jogger runs 5.0 km on a straight trail at an angle of 60° south of west.

To Find :

The southern component of the run rounded to the nearest tenth of a kilometre.

Solution :

We know, southern component is given by :

d = Dsin \ \theta\\\\d = 5\times sin \ 60^{\circ}\\\\d = -4.33\  km

Here, negative sign indicates south direction.

Therefore, the southern component of the run rounded to the nearest tenth of a kilometre is 4.3 km.

Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
What is the maximum frequency of visible light in hertz?
Nataliya [291]
All frequencies of light in hertz are in between
Red = 4 * 10 ^{14} Hz and
Violet = 8 * 10 ^{14} Hz

Light with a lower frequency than 4 * 10^14 Hz, are called infrared and can't be seen by human eye. Light with a higher frequency than 8 * 10^14 Hz, are called ultraviolet and can't bee seen by human eye. 

Therefore, the maximum frequency of visible light in Hz, is  8 * 10^14 Hz
3 0
4 years ago
The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o
WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which \mu k = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant \theta = 30^{o}.

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

           \sum F_{y} = 0

         N - W = 0

           N = W

or,      N = 75 lb

Again, equilibrium condition in the vertical direction is  as follows.

        \sum F_{x} = 0

       T_{2} - F_{k} = 0

         T_{2} = \mu_{k} N

                  = 0.4 \times 75 lb

                  = 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

         \sum F_{x} = 0

       T Cos (30^{o}) + T Cos (30^{o}) = T_{2}

          2T Cos (30^{o}) = T_{2}

    or,             T = \frac{T_{2}}{2 Cos (30^{o})}

                        = \frac{30}{2 Cos (30^{o})}

                        = \frac{30}{1.732}

                        = 17.32 lb

Now, we will calculate the output power of the motor as follows.

             P = Tv

                = 17.32 lb \times 6

                = 103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}

                = 0.189 hp

or,             = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0
3 years ago
Read 2 more answers
The photo shows two yeast cells. Each cell is an individual organism. Which sentence best describes what happened to each cell d
ratelena [41]

Answer:

C

Explanation:

This is because yeast cells replicate asexually through binary fission.

8 0
3 years ago
Read 2 more answers
A race car travels 40 m/s around a banked (45° with the horizontal) circular (radius = 0.20 km) track. What is the magnitude of
OLEGan [10]

Answer:

c)F_{net} = 0.640 kN

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

so we will have

F_{net} = ma

here we know

m = 80 kg

for circular motion acceleration is given as

a_c = \frac{v^2}{R}

a_c = \frac{40^2}{200} = 8 m/s^2

now we have

F_{net} = 80 \times 8

F_{net} = 640 N

F_{net} = 0.640 kN

7 0
3 years ago
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