Given :
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west.
To Find :
The southern component of the run rounded to the nearest tenth of a kilometre.
Solution :
We know, southern component is given by :

Here, negative sign indicates south direction.
Therefore, the southern component of the run rounded to the nearest tenth of a kilometre is 4.3 km.
Hence, this is the required solution.
All frequencies of light in hertz are in between

and

Light with a lower frequency than 4 * 10^14 Hz, are called infrared and can't be seen by human eye. Light with a higher frequency than 8 * 10^14 Hz, are called ultraviolet and can't bee seen by human eye.
Therefore, the maximum frequency of visible light in Hz, is
8 * 10^14 Hz
The given question is incomplete. The complete question is as follows.
The block has a weight of 75 lb and rests on the floor for which
= 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.
Determine the output of the motor at the instant
.
Explanation:
We will consider that equilibrium condition in vertical direction is as follows.

N - W = 0
N = W
or, N = 75 lb
Again, equilibrium condition in the vertical direction is as follows.

= 0

= 
= 30 lb
Now, the equilibrium equation in the horizontal direction is as follows.



or, T = 
= 
= 
= 17.32 lb
Now, we will calculate the output power of the motor as follows.
P = Tv
= 
= 
= 0.189 hp
or, = 0.2 hp
Thus, we can conclude that output of the given motor is 0.2 hp.
Answer:
C
Explanation:
This is because yeast cells replicate asexually through binary fission.
Answer:
c)
Explanation:
As we know that resultant force is the net force that is acting on the system
As per Newton's II law we know that net force is product of mass and acceleration
so we will have

here we know
m = 80 kg
for circular motion acceleration is given as


now we have


