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3 years ago

The area of a box is 63 sq. Inches. the length is 9 feet. what is the width

Mathematics

2 answers:

telo118 [61]3 years ago

7 0

Area = Length x Width

63 = 9 x width

Width= 63 ÷ 9 = 7 feet

Answer: 7 feet

liraira [26]3 years ago

5 0

<em>Hello there, and thank you for posting your question here on brainly.

<u>Short answer: 7
</u>
Why?

We can put this problem into an equation. Since it's a multiplication problem, we divide the known numbers. (It can either be 9 * x = 63, or 63 / 9) Divide. (63 / 9 ==> 7) The answer is 7.

Hope this helped you! ♥</em>

You might be interested in

Please answer this correctly without making mistakes

katrin2010 [14]

Answer:

16 km

Step-by-step explanation:

Given:

Distance from Washington to Stamford = distance from Washington to Salem + distance from Salem to Stamford = 10.3 km + 11.9 km = 22.2 km

Distance from Washington to Oakdele = 6.2 km

Required: the difference between the distance from Washington to Stamford and from Washington to Oakdele

Solution:

Distance from Washington to Stamford = 22.2 km

Distance from Washington to Oakdele = 6.2 km

The difference = 22.2 km - 6.2 km = 16 km

Therefore, from Washington, it is 16 km farther to Stamford than to Oakdele.

8 0

3 years ago

According to a study, 68% of all males between the ages of 18 and 24 live at home. (Unmarried college students living in a d

Marat540 [252]

Answer:

a) P(X≥143)=0

b) This contradicts the study as getting a sample with this proportion is almost impossible (if the proportion of 68% is true).

Step-by-step explanation:

If we use the normal approximation to the binomial distribution we have the following parameters (mean and standard deviation):

$\mu=np=0.68*206=140.1\\\\ \sigma=\sqrt{np(1-p)}=\sqrt{206*0.68*0.32}=\sqrt{44.8256}=6.7$

Then, we can calculate the probability of X being equal or more than 143 using the z-score:

$z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{143-140.1}{6.7/\sqrt{206}}=\dfrac{2.9}{0.4668}=6.2124\\\\\\P(x\geq143)=P(z>6.2124)=0$

This contradicts the study as getting a sample with this proportion is almost impossible (if the proportion of 68% is true).

6 0

3 years ago

Therefore, __________ and _________ because they are supplements of the same angle

Nookie1986 [14]

Complementary and supplementary.

6 0

2 years ago

QUICK!! 18x^2+21x-60=0 pls give me the steps as well

Anton [14]

Answer:

$x2 = \frac{4}{3}$

Step-by-step explanation:

$18 {x}^{2} + 21x - 60 = 0$

Divide both sides of the equation by 3

$6 {x}^{2} + 7x - 20 = 0$

Write 7x as a difference

$6 {x}^{2} + 15x - 8x - 20 = 0$

Factor out 3x from the expression

$3x(2x + 5) - 8x - 20 = 0$

Factor out -4 from the expression

$3x(2x + 5) - 4(2x + 5) = 0$

Factor out 2x + 5 from the expression

$(2x + 5)(3x - 4) = 0$

When the product of factors equals 0 , at least one factor is 0

$2x + 5 = 0$

$3x - 4 = 0$

Solve the equation for X

$2x + 5 = 0$

Move constant to R.H.S and change its sign

$2x = 0 - 5$

Calculate the difference

$2x = - 5$

Divide both sides of the equation by 2

$\frac{2x}{2} = \frac{ - 5}{2}$

Calculate

$x 1= - \frac{5}{2}$

Again,

$3x - 4 = 0$

Move constant to RHS and change its sign

$3x = 0 + 4$

Calculate the sum

$3x = 4$

divide both sides of the equation by 3

$\frac{3x}{3} = \frac{4}{3}$

Calculate

$x 2= \frac{4}{3}$

Hope this helps..

Best regards!!

5 0

3 years ago

Read 2 more answers

In the first 8 overs the bowling rate of a cricketer is 4.5, In the last two over by giving how much run the bowling rate will b

jeyben [28]

Answer:

In the last two overs, the bowler gave 14 runs.

Step-by-step explanation:

The bowling rate of 4.5 in the first 8 over means he gave 32.5 runs.

i.e.

Score given in first 8 overs = 4.5 × 8 = 36

Given that the bowling economy 5 at the end of 10 overs means the bowler must have given 10 × 5 = 50 score in the total 10 overs.

so, subtract 36 from 50 to get the score he will be giving in the last two overs.

i.e. score given the last two overs = 50 - 36 = 14

Therefore, in the last two overs, the bowler gave 14 runs.

5 0

2 years ago