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Dmitry [639]
3 years ago
14

PLEASE HELP ME WITH THIS ONE ASAP THANKS (will mark brainlest)

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0
The answer is 8000 meters I think
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Help<br><br><br><br><br><br> Thrhfjfhfhhfhfhfjf
12345 [234]

Answer: 5

Step-by-step explanation:

a^2 + b^2 = c^2

12^2 + x^2 = 13^2

144 + x^2 = 169

x^2 = 25

square root both sides

x = 5

to check, do 12^2 + 5^2 =169

sqrt of 169 is 13

hope this helps

4 0
2 years ago
The exponential function f(x) has a horizontal asymptote at y = 3. What is the
fenix001 [56]

Answer:

The function diverges to +\infty.

Step-by-step explanation:

The function diverges to +\infty.

3 0
2 years ago
a right triangle has legs of length 3x m and 4x m and hypotenuse of length 75 m. find the lengths of the legs of the triangle
just olya [345]
It is a 3-4-5 right triangle

leg1 := 3x, leg2:=4x, hypotenuse:=5x

given hypotenuse = 75m
=> 5x=75
So, x= 75÷5 = 15
Therefore, leg1 = 3(15) = 45m.
leg2= 4(15) = 60m.
4 0
2 years ago
Which of the following is not a tool that can be used in a true Geometric construction? a)Protractor b)Compass c)Straightedge
AleksAgata [21]

Answer:

A) Protractor

Step-by-step explanation:

In Mathematics, geometric constructions refers to the drawing of geometric shapes, lines and angles with the exclusive aid of a pencil, straightedge/ruler and a pair of compass.

The pencil is the major drawing tool during the construction while the pair of compass and straightedge are used to construct arcs/circles and straight lines respectively. Note that, a PROTRACTOR is not needed in a geometric construction because length or angle measurements are prohibited.

4 0
2 years ago
Read 2 more answers
Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i
liberstina [14]

Answer:

  ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

  \diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}

8 0
1 year ago
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