Answer:
The number of moles represented by 21.7 L is 0.96875 moles
Explanation:
The volume occupied by one mole of a gas which consists of (approximately) 6.022 × 10²³ elementary at STP is 22.4 L. The volume is known as the molar volume of gas
Therefore, the number of moles, 'n', present in 21.7 L of gas at STP is given as follows;
The number of moles represented by 22.4 L = 1 mole
∴ The number of moles represented by 21.7 L = 1 mole/22.4 L × 21.7 L = 0.96875 moles
The number of moles represented by 21.7 L = 0.96875 moles.
Answer:
Here's what I get
Explanation:
You have an equilibrium reaction between Fe³⁺/ SCN⁻ and FeSCN²⁺.
When you add AgNO₃, the Ag⁺ reacts with the SCN⁻. It forms a colourless precipitate of Ag(SCN).
Ag⁺(aq) + SCN⁻(aq) ⟶ AcSCN(s)
According to Le Châtelier's Principle, when we apply a stress to a system at equilibrium, the system will respond in a way that tends to relieve the stress.
If you add Ag⁺ to the equilibrium solution, it removes the SCN⁻ [as an Ag(SCN) precipitate].
The system responds by trying to replace the missing SCN⁻:
The Fe(SCN)²⁺ dissociates to form SCN⁻, so the position of equilibrium shifts to the left,
You now have more Fe³⁺ and SCN⁻ and less of the highly coloured Fe(SCN)²⁺ at the new equilibrium.
The deep red colour becomes less intense.
The sharing electrons between atoms indicates an ionic bond is FALSE.
I hope this helps
Answer:
The correct answer is because the molecular structure.
Explanation:
The difficulty of ammonia and methane to be represented on paper is due to the molecular structure. These compounds have a three-dimensional projection with defined angles. Ammonia presents angles of 109.5º between the atom of Nitrogen and those of Oxygen. The ammonia presents 107.8º between the oxygen atoms.
In the methane molecule, there is 109.5º between the hydrogen molecules and the carbon atom. This results in the need for a 3D representation of the molecule.
Have a nice day!
