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2 years ago

How many ml of a 6.00M HNO would be required to prepare 200ml of a 2.50M

Chemistry

1 answer:

Sergio039 [100]2 years ago

4 0

Answer:

83.33ml

Explanation:

Firstly, let's notice that 200ml are equal to 0.2L

M=number of moles of the solute ÷ number of liters. Let's call the number of liter by x:

2.5=x÷0.2

x=2.5×0.2

x=0.5

It means you'll need 0.5 mol of HNO. But your solution have 6 moles per liter, so how much do you need? Divide the moles by 12 to have 0.5, so now you need to divide the liter per 12 too. The liter is equal to 1000ml, so:

1000ml÷12=83.33ml

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3 years ago

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Answer:

0.846 moles.

Explanation:

This is a stichiometric problem.

The balanced equation of complete combustion of butane is:

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Using cross multiplication:

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3 years ago

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3 years ago

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The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

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$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

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