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4 years ago

Which solute will result in a molecular solution?

Chemistry

1 answer:

GuDViN [60]4 years ago

5 0

Answer:

d. CH3CH2OH

Explanation:

Molecular solution are solutions when a molecular compound is dissolved in them.

CH3CH2OH represents Ethanol or alcohol carrying "OH" group and is a molecule. CH3CH2OH or Ethanol forms a molecular solution in water.

The equation for Ethanol dissolving in water as follows:

CH3CH2OH(l) => CH3CH2OH(aq)

CH3CH2OH srays together as molecules. During dissolving, ethanol molecule fit into spaces between water molecules and completely mix with water.

While HCN, CH3COOH and Ba(OH)2 form ionic solution.

Hence, the correct option is d. CH3CH2OH.

You might be interested in

At 25.0°C the Henry's Law constant for dinitrogen monoxide (N2O) gas in water is 0.025 M/atm.

Paladinen [302]

Answer:

The mass in grams of N₂O gas that can be dissolved is 0.18 g

Explanation:

The solubility of a gas is proportional to the partial pressure of that gas, over a determined solvent. That's what Henry's law states. We see the formula:

S = K . Pp

Where S is solubility and K is Henry's constant. This specific for each gas and each temperature, while Pp means partial pressure.

We replace data:

S = 0.025 M/atm . 0.69atm

S = 0.01725 M

This is the solubility of the gas, so now, we need to know what mass of gas is solubilized. We convert the moles, with the volume of water.

0.01725 mol/L . 0.235 L = 4.05×10⁻³ moles

Now, we determine the mass in grams: 4.05×10⁻³ mol . 28 g / 1mol =

0.1782 g

5 0

3 years ago

Measure the mass to the nearest 0.01 g

Anni [7]

Measure which mass? I recommend editing the question so that I can answer it and get more points >:)

6 0

3 years ago

Florida has mild winters due to which system?

Lerok [7]

Answer: Predominant tropical easterly winds sweep across the central and southern portions of the state, keeping the temperatures mild

Explanation:

5 0

2 years ago

A certain liquid X has a normal boiling point of 108.30 °C and a boiling point elevation constant Kb=1.07 °C kg/mol. A solution

Fynjy0 [20]

Answer:

34,6g of (NH₄)₂SO₄

Explanation:

The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:

ΔT = kb×m

Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.

For the problem:

ΔT = 109,7°C-108,3°C = 1,4°C

kb = 1.07 °C kg/mol

Solving:

m = 1,31 mol/kg

As mass of X = 600g = 0,600kg:

1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:

0,785 moles of ions× $\frac{1(NH_{4})_{2}SO_{4}}{3Ions}$ = 0,262 moles of (NH₄)₂SO₄

As molar mass of (NH₄)₂SO₄ is 132,14g/mol:

0,262 moles of (NH₄)₂SO₄× $\frac{132,14g}{1mol}$ = <em>34,6g of (NH₄)₂SO₄</em>

I hope it helps!

7 0

4 years ago

Determine the theoretical yield of P2O5, when 3.07 g of P reacts with 6.09 g of oxygen in the following chemical equation 4 P+5O

icang [17]

Answer:

7.03g

Explanation:

4P + 5O2 → 2P2O5

Let us convert the mass given to mole. This can be achieved by doing the following:

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 = 6.09g

Number of mole = Mass /Molar Mass

Number of mole of O2 = 6.09/32 = 0.19mol

Molar Mass of P = 31g/mol

Mass of P = 3.07g

Number of mole of P = 3.07/31 = 0.099mol

Let us determine the limiting reactant and the excess reactant

From the equation,

4moles of P required 5moles of O2.

Therefore, 0.099mol of P will require = (0.099 x 5)/4 = 0.12mol

From the above illustration, we see clearly that not all the O2 reacted as the number of mole of O2 obtained from the question is 0.19mol. This means that O2 is the excess reactant and P is the limiting reactant.

Note: the limiting reactant is always used to obtain the yield of any reaction.

Now we can obtain the theoretical yield of P2O5 as follows:

4P + 5O2 → 2P2O5

Molar Mass of P = 31g/mol

Mass of P from the equation = 4x31 = 124g

Molar Mass of P2O5 = (31x2) + (16x5) = 62 + 80 = 142g/mol

Mass of P2O5 from the equation = 2 x 142 = 284g

From the equation,

124g of P produced 284g of P2O5.

Therefore, 3.07g of P will produce = (3.07x284)/124 = 7.03g of P2O5.

Therefore, the theoretical yield of P2O5 is 7.03g

4 0

4 years ago