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djyliett [7]
3 years ago
15

Kareem lives 4/10 of a mile from the mall. Write twp equivalent fractions that show what fraction of a mile Kareem lives from th

e mall.
Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:


Step-by-step explanation:

4/10 can be written in several different ways:

2/5, 40/100 (same as 0.4).

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Maya can run 18 miles in 3 hours, and she can bike 18 miles in 2 hours. When Maya biked for 3 hours and then ran for 1 hour and
solmaris [256]

Answer: 8

Step-by-step explanation: Speed is distance/time

18/3 = 6 miles per hour running

18/2 = 9 miles per hour biking

3 hour bike = 27 miles

1.50 hour run (0.50 because 30 minutes is half of an hour) = 9 miles

27 + 9/3 + 1.50 = 36/4.5 or 8

4 0
3 years ago
Y=3x\4 if y= -6 find the value of x<br>please answer this for me, it's graded​
sveticcg [70]

Answer:

x = -8

Step-by-step explanation:

y = 3x/4

Substitute the value of -6 into y.

-6 = 3x/4

Multiply both sides by 4.

-24 = 3x

Divide both sides by 3.

x = -8.

4 0
2 years ago
Read 2 more answers
List three ways to express 3^5 as a product of powers
adelina 88 [10]
3^5
3 x 3 x 3
3:5 <- I think
3 0
2 years ago
Read 2 more answers
Show your work<br> −126 = 14k
Yuliya22 [10]

Answer: k = -9

Step-by-step explanation:

-126 = 14k

-------  -------

 14     14

-126 divided by 14 = -9

k = -9

4 0
3 years ago
A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are
Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0
2 years ago
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