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damaskus [11]
4 years ago
11

M=100g V=5cm^3 what is the density?

Chemistry
1 answer:
Aleks [24]4 years ago
5 0
D =  \frac{mass}{volume}  \\ D =  \frac{100}{5}  = 20  \frac{g}{cm^3}
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The average blood volume in the human body is about 4.9 L. Convert this volume to cubic centimeters (cm3).a. milliliters (mL)b.
CaHeK987 [17]

Answer:

a. 4900 mL; b. 4900 cm³ c. 4.9x10⁻³  m³

Explanation:

1 L = 1 dm³

4.9 L = 4.9 dm³

1 dm³ = 1000 cm³  → 4900 cm³

1 cm³ = 1 mL  (4900 mL)

1 dm³ = 1x10⁻³ m³ → 4.9x10⁻³  m³

6 0
3 years ago
Is it easy for gallium to change from solid to liquid? Why<br> subject is science
Alekssandra [29.7K]

Answer:

Solid gallium is a blue-gray metal with orthorhombic crystalline structure; very pure gallium has a stunning silvery color. Gallium is solid at normal room temperatures, but as well as mercury, cesium, and rubidium it becomes liquid when heated slightly

Explanation:

gallium is like water it freezes to turn solid!

...or like Bruce lee get it?

5 0
3 years ago
Consider the following molecules and the description of the bonding present in each: CH3CH2CH2CH3CH3CH2CH2CH3 (C−CC−C and C−HC−H
denis23 [38]

CH3CH2CH2CH3 < CH3CH2CHO < CH3CHOHCH3

Explanation:

Boiling point trend of Butane, Propan-1-ol and Propanal.

Butane is a member of the CnH2n+2 homologous series is an alkane. Alkanes have C-H and C-C bonds which have Van der waals dispersion forces which are temporary dipole-dipole forces (forces caused by the electron movement in a corner of the atom). This bond is weak but increases as the carbon chain/molecule increases.

In Propan-1-ol(Primaryalcohol), there is a hydrogen bond present in the -OH group. Hydrogen bond is caused by the attraction of hydrogen to a highly electronegative element like Cl-, O- etc. This bond is stronger than dispersion forces because of the relative energy required to break the hydrogen bond. Alcohols (CnH2n+1OH) also experience van der waals dispersion forces on its C-C chain and C-H so as the Carbon chain increases the boiling point increases in the homologous series.

Propanal which is an Aldehyde (Alkanal) with the general formula CnH2n+1CHO. This molecule has a C-O, C-C and C-H bonds only. If you notice, the Oxygen is not bonded to the Hydrogen so there is no hydrogen bond but the C-O bond has a permanent dipole-dipole force caused by the electronegativity of oxygen which is bonded to carbon. It also has van der waals dispersion forces caused by the C-C and C-H as the carbon chain increases down the homologous series. The permanent dipole-dipole forces are not as easy to break as van der waals forces.

In conclusion, the hydrogen bonds present in alcohols are stronger than the permanent dipole-dipole bonds in the aldehyde and the van der waals forces in alkanes (irrespective of the carbon chain in Butane). So Butane < Propanal < Propan-1-ol

3 0
3 years ago
How do animals receive the sun's energy?
Elza [17]

Answer:

Explanation:

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4 0
3 years ago
Which of the following has 62 neutrons, 46 protons, and 46 electrons?​
Vesna [10]
The answer is Silver (Ag)
6 0
3 years ago
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