Question

The pressure inside an aerosol can is 3.80 atm at 25.0°C. If the temperature is increased from 25.0°C to 100.0°C, what would be

Answer 1

Answer:

B. 4.76 atm

Explanation:

$P_1$ = Initial pressure = 3.8 atm

$T_1$ = Initial temperature = $25+273.15\ \text{K}$

$P_2$ = Final pressure

$T_2$ = Final temperature = $100+273.15\ \text{K}$

From Gay Lussac's law we have

$\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\\Rightarrow P_2=P_1\dfrac{T_2}{T_1}\\\Rightarrow P_2=3.8\times\dfrac{100+273.15}{25+273.15}\\\Rightarrow P_2=4.76\ \text{atm}$

The pressure inside the can would be $4.76\ \text{atm}$.