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jeka94
3 years ago
12

The pressure inside an aerosol can is 3.80 atm at 25.0°C. If the temperature is increased from 25.0°C to 100.0°C, what would be

Chemistry
1 answer:
ladessa [460]3 years ago
7 0

Answer:

B. 4.76 atm

Explanation:

P_1 = Initial pressure = 3.8 atm

T_1 = Initial temperature = 25+273.15\ \text{K}

P_2 = Final pressure

T_2 = Final temperature = 100+273.15\ \text{K}

From Gay Lussac's law we have

\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\\Rightarrow P_2=P_1\dfrac{T_2}{T_1}\\\Rightarrow P_2=3.8\times\dfrac{100+273.15}{25+273.15}\\\Rightarrow P_2=4.76\ \text{atm}

The pressure inside the can would be 4.76\ \text{atm}.

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A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h <u>. Ksp=1.9×10⁻⁸</u>

<h3>What is titration?</h3>

Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.

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1 year ago
How many total atoms are in 0.290 g of P2O5?
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Step 1. Convert <em>grams of P₂O₅ to moles of P₂O₅</em>.

\text{Moles of P}_{2}\text{O}_{5} = \text{0.290 g } \text{P}_{2}\text{O}_{5} \times \frac{\text{1 mol }\text{P}_{2}\text{O}_{5}}{\text{141.94 g }\text{P}_{2}\text{O}_{5}} = \text{0.002 043 mol } \text{P}_{2}\text{O}_{5} \\

Step 2. Convert <em>moles of P₂O₅ to molecules of P₂O₅</em>.

\text{Molecules of } \text{P}_{2}\text{O}_{5} = \text{0.002 043 mol } \text{P}_{2}\text{O}_{5} \times \frac{6.022 \times 10^{23}\text{ molecules }\text{P}_{2}\text{O}_{5}}{\text{1 mol } \text{P}_{2}\text{O}_{5}}\\

= 1.23 \times10^{21}\text{ molecules } \text{P}_{2}\text{O}_{5}\\

Step 3. Convert <em>molecules of P₂O₅ to atoms</em>.

There are seven atoms in 1 mol P₂O₅.

∴ \text{Total atoms} = 1.23\times 10^{21 }\text{ molecules }\text{P}_{2}\text{O}_{5} \times\frac{\text{7 atoms}}{\text{1 molecule }\text{P}_{2}\text{O}_{5}} = 8.61 \times 10^{21}\text{ atoms}\\

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