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Leviafan [203]
3 years ago
8

What is the mass of an object if the density is 7.85g/l and the volume is 41.25ml

Chemistry
1 answer:
Blababa [14]3 years ago
7 0
The density is the ratio between mass and volume. So the mass is the product between density and volume. But! You have to control the units of measure.

7.85 g/l = 0.00785 kg/l

41.25 ml = 0.04125 l

Mass = (0.00785) x (0.04125) = 0,00032381 kg ---> 0,32381 g

(I hope this is right )
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What is the relationship between the internal energy of a substance and its particle movement?
ss7ja [257]

Answer: The closeness, arrangement and motion of the particles in a substance change when it changes state. Materials are a store of internal energy , due to the motion of particles and the chemical bonds between them. When a substance is heated, its internal energy increases: the movement of its particles increases.

Explanation:

6 0
3 years ago
Is O2 always a double bond?
Dima020 [189]
  • O-O single bonds and H-O single bonds in \text{H}_2\text{O}_2 molecules.
  • H-O single bonds in \text{H}_2\text{O} molecules.
  • O=O double bonds in \text{O}_2 molecules.
<h3>Explanation</h3>

How many valence electrons do atoms in each molecule need for them to be stable?

  • Each H atom needs two valence electrons to be stable.
  • Each atom of an element other than H needs eight valence electron to be stable.
  • There are two H atoms and two O atoms in an  \text{H}_2\text{O}_2 molecule. Atoms in each \text{H}_2\text{O}_2 need 2 \times 1 + 2\times 2 = 6 more electrons to be stable.
  • There are two H atoms and one O atom in an \text{H}_2\text{O} molecule. Atoms in each \text{H}_2\text{O} molecule need 2 \times 1 + 2= 4 more electrons to be stable.
  • There are two O atoms in an \text{O}_2 molecule. Atoms in each \text{O}_2 molecule need 2 \times 2 = 4 more electrons to be stable.

How many chemical bonds in each molecule?

Each chemical bond adds one valence electron to each bonding atom. Each chemical bond connects two atoms. As a result, each chemical bond adds two valence electrons to the molecule.

  • Each \text{H}_2\text{O}_2 molecule needs 6 / 2 = 3 chemical bonds.
  • Each \text{H}_2\text{O} molecule needs 4 / 2 = 2 chemical bonds.
  • Each \text{O}_2 molecule needs 4 /2= 2 chemical bonds.

What chemical bonds are these? Again, each H atom needs only one more valence electron to be stable. It will share only one electron with O and form one H-O bond. The rest of the chemical bonds are between O atoms.

  • There are two H atoms in each \text{H}_2\text{O}_2 molecule, which form two H-O bonds. Two of the three chemical bonds in this molecule are H-O. The other is an O-O single bond between the two O atoms.
  • There are two H atoms in each \text{H}_2\text{O} molecule, which form two H-O bonds. Both chemical bonds in this molecule are H-O. There's no O-O bond in this molecule.
  • There is no H atom in \text{O}_2 molecules. Both chemical bonds are between O atoms. However, there are only two O atoms. There must be two chemical bonds between the two O atoms. That bond will be an O-O double bond.
3 0
2 years ago
Read 2 more answers
λmax for the π → π* transition in ethylene is 170 nm. Is the HOMO-LUMO energy difference in ethylene greater than or less than t
-Dominant- [34]

Answer:

the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

Explanation:

The λmax is the wavelength of maximum absorption. We could use it to calculate the HOMO-LUMO energy difference as follows:

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E= hc/λ= 6.63×10^-34×3×10^8/170×10^-9= 1.17×10^-18J

For cis,trans−1,3−cyclooctadiene

E= hc/λ=6.63×10^-34×3×10^8/230×10^-9=8.6×10^-19J

Therefore, the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

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2 years ago
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Gala2k [10]

Answer:

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n =?

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Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M = \frac{m}{n} ⇔ n = \frac{m}{M} ⇔ n = \frac{3.06 x 10^{-3} }{5,05} ⇔ n = 6.06 x 10^{-4} mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.

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