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Vitek1552 [10]
3 years ago
7

How many formula units are present in 25.0 mol of sodium chloride

Chemistry
1 answer:
bonufazy [111]3 years ago
7 0
The way to work out formula units is to do the amount of moles (in this case 25) times by 6.022 x 10^23. so, the answer is 1.5055 x 10^25 formula units. hope this helps! (by the way ^ represents ‘to the power of’ because i cant get the smaller symbols on here)
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What volume in mt, of 0.5a M1HCI solution is needed to neutralize 77 ml of 1.54 M NaOH solution?
Rainbow [258]

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237.2 mL.

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  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

(XMV) acid = (XMV) base.

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HCl = (XMV) NaOH.</em>

<em></em>

For HCl; X = 1, M = 0.5 M, V = ??? mL.

For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.

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