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mart [117]
4 years ago
10

Find the exponent A in the equation

Physics
1 answer:
hodyreva [135]4 years ago
5 0
Start by swapping the variables in the equations with their units (leave A alone for now): v=\frac{a^2t^A}{x} \Rightarrow  \frac{L}{T} =  \frac{ (\frac{L}{T^2})^2 T^A }{L}

Multiply by L and square the fraction: \frac{L^2}{T} =  \frac{L^2}{T^4} T^A \Rightarrow  \frac{L^2}{T} \div  \frac{L^2}{T^4}=T^A

Divide the fraction by multiplying by the reciprocal: \frac{L^2}{T} \times  \frac{T^4}{L^2} = T^A \Rightarrow T^3=T^A

Therefore A=3
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Answer:

231.98 mL

Explanation:

V₁ = Initial volume = 205 mL

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P₂ = Final pressure = 750 mmhg (STP)

T₁ = Initial temperature = -44 °C = 229.15 K

T₂ = Final temperature = 273.15 K (STP)

From Combined gas law

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\Rightarrow V_2=\frac{P_1V_1T_2}{T_1P_2}\\\Rightarrow V_2=\frac{712\times 205\times 273.15}{229.15\times 750}=231.98\ mL

Volume of the argon at STP is 231.98 mL

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an oscilloscope has a time/div setting of 50ms and there are 10 divisions on the time scale. a sine wave on the oscilloscope dis
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Answer:

The frequency is f = 6Hz

Explanation:

Given

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         The number of division is  n= 10

The total time for 10 division can be mathematically obtained as

         T_{total} = 10 *50*10^{-3}

                 =500 *10^{-3}s

From the question the time for 3 cycle is

        T_{total} = 500*10^{-3}s

Then the for one cycle which equivalent to the Period(T)  =  \frac{T_{total}}{3}

                                                               = \frac{500 *10^{-3}}{3}

The frequency is generally given as    f = \frac{1}{period} = \frac{1}{T}

    Now substituting values we have  

                              f = \frac{3}{500 *10^{-3}}

                                 = 6Hz

                 

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Answer:

False

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