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4vir4ik [10]
3 years ago
8

When the velocity of a moving object stays the same, it has a what speed

Physics
1 answer:
Molodets [167]3 years ago
8 0
Same rate of change of distance but velocity include circular motion and known as vector quantity but speed is scalar quantity only.
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What is the formula for mechanical advantage?
Sladkaya [172]

Answer:

A. MA=force output/force input

Explanation:

mechanical advantage is the ratio of the load to the effort

8 0
3 years ago
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A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105m above the Earth, a package is dropped from a w
Luden [163]

Here it is given that initial speed of the package will be same as speed of the helicopter

v_i = 5.10 m/s

displacement of the package as it is dropped on ground

d = -105 m

acceleration is due to gravity

a = -9.8 m/s^2

now by kinematics

y = v* t + \frac{1}{2}at^2

-105 = 5.1 * t - \frac{1}{2}*9.8*t^2

4.9 t^2 - 5.1 t - 105 = 0

by solving above equation we have

t = 5.2 s

so it will take 5.2 s to reach the ground

7 0
3 years ago
As an intern with an engineering firm, you are asked to measure the moment of inertia of a large wheel, for rotation about an ax
AysviL [449]

Answer:

I=2.766\ kg.m^2

Explanation:

We have:

diameter of the wheel, d=0.88\ m

weight of the wheel, w_w=280\ N

mass of hanging object to the wheel, m_o=6.32\ kg

speed of the hanging mass after the descend, v_o=4\ m.s^{-1}

height of descend, h=2.5\ m

(a)

moment of inertia of wheel about its central axis:

I=\frac{1}{2} m.r^2

I=\frac{1}{2} \frac{w_w}{g}.r^2

I=\frac{1}{2} \times \frac{280}{9.8}\times 0.44^2

I=2.766\ kg.m^2

3 0
3 years ago
A coil has 400 turns and self-inductance 7.50 mH. The current in the coil varies with time according to i = 1680 mA2 cos [πt/(0.
zhannawk [14.2K]

Answer:

(a) 1.58 V

(b) 0.0126 Wb

(c) 0.0493 V

Solution:

As per the question:

No. of turns in the coil, N = 400 turns

Self Inductance of the coil, L = 7.50 mH = 7.50\times 10^{- 3}\ H

Current in the coil, i = 1680cos[\frac{\pi t}{0.0250}] A

where

i_{max} = 1680\ mA = 1.680\ A

Now,

(a)  To calculate the maximum emf:

We know that maximum emf induced in the coil is given by:

e = \frac{Ldi}{dt}

e = L\frac{d}{dt}(1680)cos[\frac{\pi t}{0.0250}]

e = - 7.50\times 10^{- 3}\times \frac{\pi}{0.0250}\times \frac{d}{dt}(1680)sin[\frac{\pi t}{0.0250}]

For maximum emf, sin\theta should be maximum, i.e., 1

Now, the magnitude of the maximum emf is given by:

|e| = 7.50\times 10^{- 3}\times 1680\times 10^{- 3}\times \frac{\pi}{0.0250} = 1.58\ V

(b) To calculate the maximum average flux,we know that:

\phi_{m, avg} = L\times i_{max} = 7.50\times 10^{- 3}\times 1.680 = 0.0126\ Wb

(c) To calculate the magnitude of the induced emf at t = 0.0180 s:

e = e_{o}sin{\pi t}{0.0250}

e = 7.50\times 10^{- 3}\times sin{\pi \times 0.0180}{0.0250} = 2.96\times 10^{- 4} =0.0493\ V

7 0
3 years ago
The diagram shows a wave traveling through a medium.
m_a_m_a [10]
The answer is b. The crest.

Hope this helps!
6 0
3 years ago
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