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jeyben [28]
2 years ago
6

If a 4kg Bird is pushed by the window with a force of 60 N how fast is the bird accelerate?

Physics
1 answer:
LiRa [457]2 years ago
3 0
  • Force=60N
  • Mass=4kg

\\ \ast\sf\hookrightarrow Force=Mass\times Acceleration

\\ \ast\sf\hookrightarrow Acceleration=\dfrac{Force}{Mass}

\\ \ast\sf\hookrightarrow Acceleration=\dfrac{60}{4}

\\ \ast\sf\hookrightarrow Acceleration=15m/s^2

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frez [133]

Answer:

91.3°F

Explanation:

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And m, c, h are all constants from the cooling law relation

From Newton's law of cooling

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(d/dt) (T - T∞) = dT/dt (Because T∞ is a constant)

dT/dt = (-h/mc) (T - T∞)

Let (h/mc) be k

dT/(T - T∞) = -kdt

Integrating the left hand side from T₀ to T and the right hand side from 0 to t

In [(T - T∞)/(T₀ - T∞)] = -kt

(T - T∞)/(T₀ - T∞) = e⁻ᵏᵗ

(T - T∞) = (T₀ - T∞)e⁻ᵏᵗ

Inserting the known variables

(T - 70) = (212 - 70)e⁻ᵏᵗ

(T - 70) = 142 e⁻ᵏᵗ

At t = 2 minute, T = 125°F

125 - 70 = 142 e⁻ᵏᵗ

55/142 = e⁻ᵏᵗ

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- k(2) = - 0.9485

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kt = 0.4742 × 4 = 1.897

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e^(-1.897) = 0.15

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T = 91.3°F

7 0
3 years ago
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Hope that this was helpful :)

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