Answer:
bc earth rotates
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Explanation:
Answer:
14.17H
Explanation:
Energy stored in an inductor is expressed as;
E = 1/2LI²
L is the inductance of the inductor
I is the current flowing through the inductor
Given
E = 10.2J
I = 1.20
Required
Inductance L
Substitute the given parameters into the formula;
10.2 = 1/2L(1.2)²
10.2 = 1/2*1.44L
10.2 = 0.72L
L = 10.2/0.72
L = 14.17H
Hence the self inductance of the solenoid is 14.17H
The objects that we now see as comets and asteriods form in th solar system after solid particles condensed from the gas but before the planets finished forming. So the asteriods and comets form in the solar system that is the object that we see after the solid particles condensed from the gas but before the planet finished forming.
To solve this problem we will apply the concepts related to centripetal acceleration, which will be the same - by balance - to the force of gravity on the body. To find this acceleration we must first find the orbital velocity through the Doppler formulas for the given periodic signals. In this way:
Here,
Orbital Velocity
Maximal Wavelength
Average Wavelength
c = Speed of light
Replacing with our values we have that,
<em>Note that the average signal is 3.000000m</em>
Now using the definition about centripetal acceleration we have,
Here,
v = Orbit Velocity
r = Radius of Orbit
Replacing with our values,
Applying Newton's equation for acceleration due to gravity,
Here,
G = Universal gravitational constant
M = Mass of the planet
r = Orbit
The acceleration due to gravity is the same as the previous centripetal acceleration by equilibrium, then rearranging to find the mass we have,
Therefore the mass of the planet is
Answer:
E₄ = - 0.85 eV
E₂ = - 3.4 eV
Ephoton = 2.55 eV
Explanation:
The sum of Kinetic Energy (K) and Potential Energy (U) of the Helium atom is equal to the total energy of Helium atom in the specified state N. From Bohr's atomic model, the energy of a hydrogen atom in state N is given as:
En = K + U = (-1/n²)(13.6 eV)
a)
Here,
n = 4
Therefore,
E₄ = (-1/4²)(13.6 eV)
<u>E₄ = - 0.85 eV</u>
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b)
Here,
n = 2
Therefore,
E₂ = (-1/2²)(13.6 eV)
<u>E₂ = - 3.4 eV</u>
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c)
The energy of photon emitted in the transition from level 4 to level 2 will be equal to the difference in the energy of both levels:
Ephoton = ΔE = E₄ - E₂
Ephoton = - 0.85 eV - (- 3.4 eV)
<u>Ephoton = 2.55 eV</u>
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