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serious [3.7K]
2 years ago
5

Please hurry! 30 points

Physics
1 answer:
Cloud [144]2 years ago
4 0

Answer:

50.000

Explanation:

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Most calculators operate on 6.0 V. If, instead of using batteries, you obtain 6.0 V from a transformer plugged into 110-V house
Vika [28.1K]

Answer:

1/0.0545

Explanation:

The transformer have a ratio of the primary turns to the secondary turns equivalent to the ratio of the voltage it is changing. If we have 6.0 V in the secondary (output), and 110 V in the primary (input) the ratio of the voltage is 6/110 = 0.0545, so the ratio between turns in the transformer is 1/0.0545 (for each turn in the primary, the transformer has 0.0545 turns in secondary)

6 0
3 years ago
n a distant solar system, a planet of mass 5.0 x 1024 kg orbits a sun of mass 3.0 x 1030 kg at a constant distance of 2.0 x1011
Anna35 [415]

Answer:

F = M2 ω^2 R       centripetal force of sun on planet

ω = (F / (M2 R))^1/2 = 2 pi f = 2 pi / P        where P is the period

P = 2 pi (M2 * R / F)^1/2

F = G M1 M2 / R^2        gravitational force on planet

P = 2 pi {R^3 / (G M1)]^1/2

P = 6.28 [(2.0E11)^3 / (6.67E-11 * 3.0E30)]^1/2

P = 6.28 (8 / 20)^1/2 E7 = 3.9E7 sec

1 yr = 3600 * 24 * 365 = 3.15E7 sec

P = 3.9 / 3.2 = 1.2 years

4 0
2 years ago
In his novel From the Earth to the Moon (1866), Jules Verne describes a spaceship that is blasted out of 12,000 yards/s. the Col
saw5 [17]

Answer:

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

Explanation:

Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (a), measured in meters per square second, is estimated by this kinematic formula:

a = \frac{v^{2}-v_{o}^{2}}{2\cdot \Delta s } (1)

Where:

\Delta s - Travelled distance, measured in meters.

v_{o}, v - Initial and final speeds of the spaceship, measured in meters.

If we know that v_{o} = 0\,\frac{m}{s}, v = 10968\,\frac{m}{s} and \Delta s = 212.8\,m, then the acceleration experimented by the spaceship is:

a = \frac{\left(10968\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (212.8\,m)}

a = 282652.782\,\frac{m}{s^{2}}

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

5 0
3 years ago
The hydraulic lift in a car repair shop has an output diameter of 30 cm and is to lift cars up to 2000 kg. determine the fluid g
leonid [27]
Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2

Thank you for posting your question here at brainly. I hope the answer helps. </span>
4 0
3 years ago
Read 2 more answers
Is cell using oxygen to break down sugar a physical or chemical change
Viefleur [7K]
Breaking down sugar (glucose) is a chemical change. Sugar is a compound that can be broken down.
5 0
3 years ago
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