Please hurry! 30 points

Projectiles that strike objects are good examples of inelastic collisions. A 0.1 kg nail driven by a gas powered nail driver col

Ratling [72]

In an inelastic collision, only momentum is conserved, while energy is not conserved.

1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
$p_f=(m+M)v_f=4.8 kg m/s$
where
m=0.1 kg is the mass of the nail
M=10 kg is the mass of the block of wood
Rearranging the formula, we find $v_f$ , the velocity of the nail and the block after the collision:
$v_f= \frac{p_f}{m+M}= \frac{4.8 kg m/s}{0.1 kg+10 kg}= 0.48 m/s$

2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:
$p_i = mv_i = p_f$
Rearranging the formula, we can find $v_i$ , the velocity of the nail before the collision:
$v_i = \frac{p_f}{m}= \frac{4.8 kg m/s}{0.1 kg}=48 m/s$

6 0

3 years ago

Read 2 more answers

Which of the following simple machines is not properly identified? A. Scissors: lever B. Pizza cutter: wedge C. Screw: wheel and

GrogVix [38]

Pretty sure the answer is C. Screw: wheel and axle

8 0

3 years ago

A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 m

jonny [76]

Answer:

Speed of motorcycle is 40 mph and speed of car is 50 mph

Explanation:

Let the peed f the motorcycle is v m /sec

According to question speed of motorcycle = 2v-30 mph

Now it is given that in two hours car is 20 miles ahead from motorcycle

Distance traveled by motorcycle in 2 hour = 2v

And distance traveled by car in two hour = 2×(2v-30)

Now according to question

$2(2v-30)=2v+20$

4v-60 = 2v+20

2v = 80

v = 40 mph

So speed of motorcycle is 40 mph

And speed of car = 2v-30 = 2×40-30 = 50 mph

6 0

3 years ago

Suppose the moon were held in its orbit not by gravity but by a massless cable attached to the center of the earth. What would b

Mars2501 [29]

Answer:

$1.98\cdot 10^{20} N$

Explanation:

The tension in the cable would be then equal to the gravitational force that keeps the Moon in circular orbit around the Earth. So, we just need to calculate the magnitude of this force, which is given by:

$F=G\frac{mM}{r^2}$