Answer:
1/0.0545
Explanation:
The transformer have a ratio of the primary turns to the secondary turns equivalent to the ratio of the voltage it is changing. If we have 6.0 V in the secondary (output), and 110 V in the primary (input) the ratio of the voltage is 6/110 = 0.0545, so the ratio between turns in the transformer is 1/0.0545 (for each turn in the primary, the transformer has 0.0545 turns in secondary)
Answer:
F = M2 ω^2 R centripetal force of sun on planet
ω = (F / (M2 R))^1/2 = 2 pi f = 2 pi / P where P is the period
P = 2 pi (M2 * R / F)^1/2
F = G M1 M2 / R^2 gravitational force on planet
P = 2 pi {R^3 / (G M1)]^1/2
P = 6.28 [(2.0E11)^3 / (6.67E-11 * 3.0E30)]^1/2
P = 6.28 (8 / 20)^1/2 E7 = 3.9E7 sec
1 yr = 3600 * 24 * 365 = 3.15E7 sec
P = 3.9 / 3.2 = 1.2 years
Answer:
The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.
Explanation:
Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (
), measured in meters per square second, is estimated by this kinematic formula:
(1)
Where:
- Travelled distance, measured in meters.
, 
- Initial and final speeds of the spaceship, measured in meters.
If we know that 
, 
and 
, then the acceleration experimented by the spaceship is:
The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.
Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2
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Breaking down sugar (glucose) is a chemical change. Sugar is a compound that can be broken down.
