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MaRussiya [10]
3 years ago
9

When talking about variables in a scientific experiment, describe how you know what the independent variable, dependent variable

, control and constant are in the experiment. How do you know which one is which?
Physics
2 answers:
Mnenie [13.5K]3 years ago
4 0

An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.

STatiana [176]3 years ago
3 0
<h2>Answer and Explanation </h2>

An independent variable is a variable which changes to examine the impacts on the dependent variable. On the other hand, the dependent variable is the factor which is changed due to change of independent variable. It is being examined. Constant is a value which remains the same throughout the experiment. Control is the substances or things which protect the experiment from any danger due to scientific research.  

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A metal cylinder with a mass of 4.20 kg is attached to a spring and is able to oscillate horizontally with negligible friction.
kherson [118]

Answer:

a) k = 120 N / m

, b)    f = 0.851 Hz

, c)  v = 1,069 m / s

, d)  x = 0

, e)  a = 5.71 m / s²

, f)   x = 0.200 m

, g)  Em = 2.4 J

, h) v = -1.01 m / s

Explanation:

a) Hooke's law is

         F = k x

         k = F / x

          k = 24.0 / 0.200

          k = 120 N / m

b) the angular velocity of the simple harmonic movement is

        w = √ k / m

        w = √ (120 / 4.2)

        w = 5,345 rad / s

Angular velocity and frequency are related.

       w = 2π f

        f = w / 2π

        f = 5.345 / 2π

        f = 0.851 Hz

c) the equation that describes the movement is

        x = A cos (wt + Ф)

As the body is released without initial velocity, Ф = 0

        x = 0.2 cos wt

Speed ​​is

       v = dx / dt

       v = -A w sin wt

The speed is maximum for sin wt = ±1

       v = A w

       v = 0.200 5.345

       v = 1,069 m / s

d) when the function sin wt = -1 the function cos wt = 0, whereby the position for maximum speed is

       x = A cos wt = 0

       x = 0

e) the acceleration is

       a = d²x / dt² = dv / dt

       a = - Aw² cos wt

The acceleration is maximum when cos wt = ± 1

       a = A w²

        a = 0.2   5.345

        a = 5.71 m / s²

f) the position for this acceleration is

       x = A cos wt

       x = A

       x = 0.200 m

g) Mechanical energy is

        Em = ½ k A²

        Em = ½ 120 0.2²

       Em = 2.4 J

h) the position is

         x = 1/3 A

Let's calculate the time to reach this point

         x = A cos wt

        1/3 A = A cos 5.345t

         t = 1 / w cos⁻¹(1/3)

The angles are in radians

t = 1.23 / 5,345

t = 0.2301 s

Speed ​​is

v = -A w sin wt

v = -0.2 5.345 sin (5.345 0.2301)

v = -1.01 m / s

i) acceleration

a = -A w² sin wt

a = - 0.2 5.345² cos (5.345 0.2301)

      a = -1.91 m / s²

5 0
3 years ago
A gas has an initial volume of 212 cm3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the g
Marizza181 [45]
Using the pressure law (P1 x V1)/ T1 = (P2 x V2)/ T2 where P1= the initial pressure V1= initial volume T1= initial temperature and P2= the final pressure V2= the final volume T2 = the final temperature and temperature is always in kelvin

7 0
3 years ago
An object moves uniformly around a circular path of radius 19.0 cm, making one complete revolution every 2.40 s.
klio [65]

Answer:

v = 0.5 m/s

f = 0.42 Hz

ω = 2.6 rad/sec

Explanation:

  • By definition, the translational speed is the rate of change of the position with respect to time.
  • The change in position along a complete revolution is just the following:
  • Δs = 2*π*r = 2*π*0.19 m = 1.19 m
  • The time needed to complete a revolution is 2.4 s, so the translational speed can be written as follows:

        v =\frac{\Delta s}{\Delta t} = \frac{1.19m}{2.4s} = 0.5 m/s (1)

  • The frequency in Hz is just the inverse of the time needed to complete a revolution (known as the period T), as follows:
  • f = 1/T = 1/2.4s = 0.42 Hz (2)
  • Finally, the angular speed is the rate of change of the angle rotated with respect to time, as follows:

       \omega = \frac{\Delta\theta}{\Delta t} =  \frac{2*\pi}{2.4s} = 2.6 rad/sec (3)

5 0
3 years ago
What is the maximum kinetic energy of ejected electrons when photons of wavelength 300 nm hit a metal that has a work function o
Sonja [21]

Explanation:

Given that,

Wavelength of the photon, \lambda=300\ nm=3\times 10^{-7}\ m

Work function of the metal, \phi=1.13\ eV=1.81\times 10^{-19}\ J

We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :

hf=E_k+\phi

E_k=hf-\phi

E_k=h\dfrac{c}{\lambda}-\phi

E_k=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{3\times 10^{-7}}-1.81\times 10^{-19}

E_k=4.82\times 10^{-19}\ J

E_k=3.01\ eV

or

E_k=3\ eV

So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.          

3 0
3 years ago
This is a sience question
levacccp [35]
I would say A is the answer im not sure tho
3 0
3 years ago
Read 2 more answers
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