Answer:
x = 10.53 m
Explanation:
Let's analyze this problem a bit, the time that the cowboy must take to fall must be the time that the horse takes to arrive
Let's start by looking for the cowboy's time, which starts from rest and the point where the chair is is y = 0
y =y₀ + v₀ t - ½ g t²
0 = y₀ - ½ g t²
t =
we calculate
t = √(2 3.22 / 9.8)
t = 0.81 s
the horse goes at a constant speed
x = t
x = 13 0.81
x = 10.53 m
this is the distance where the horse should be when in cowboy it is left Cartesian
Explanation:
It is given that,
Let q₁ and q₂ are two small positively charged spheres such that,
.............(1)
Force of repulsion between the spheres, F = 1 N
Distance between spheres, d = 2 m
We need to find the charge on the sphere with the smaller charge. The force is given by :
............(2)
On solving the system of equation (1) and (2) using graph we get,
So, the charge on the smaller sphere is 11.6 micro coulombs. Hence, this is the required solution.
Answer:
A, B, and E
Explanation:
C and D are wrong;
Line graphs do not show the dependent variable on the x-axis.
Line graphs do have both an x-axis and a y-axis.
The Universe is always expanding outwards