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2 years ago

Which of the following characterizes Erikson's identity versus role formation stage?

Physics

2 answers:

Rainbow [258]2 years ago

7 0

I think that the best one is determining one's sense of individuality and place in society.

melamori03 [73]2 years ago

3 0

Answer:

Determining one's sense of individuality and place in society

Explanation:

This is the fifth stage of Erickson’s eight stages of psychosocial development which occurs in the age range of 12-18.

In this stage adolescent's try to figure out what kind of person they are i.e., finding one's self. In this stage people try different things to know their likes and dislikes. In order to find their likes and dislikes they try different things to understand their place in the world i.e, they will understand their role that they will occupy.

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Why can’t you hit a feather in mid air with a force of 200 N<br> (This is all the info I was given)

Aloiza [94]

You cannot for real ehhhh

5 0

2 years ago

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$

$k=\sqrt{\frac{\frac{MR^2}{2}}{M} }$

$k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }$

$k=\sqrt{{\frac{R^2}{2}}$

$k={\frac{R}{\sqrt{2}}$

$k={\frac{1.20m}{\sqrt{2}}$

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = $\frac{2}{3}MR^2$

$k = \sqrt{\frac{\frac{2}{3}MR^2}{M} }$

$k = \sqrt{\frac{2}{3} R^2}$

$k = \sqrt{\frac{2}{3} }*R$

$k = \sqrt{\frac{2}{3}} *1.20$

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of radius

(I) = $\frac{2}{5}MR^2$

$k = \sqrt{\frac{\frac{2}{5}MR^2}{M} }$

$k = \sqrt{\frac{2}{5} R^2}$

$k = \sqrt{\frac{2}{5} }*R$

$k = \sqrt{\frac{2}{5}} *1.20$

k = 0.7560

k ≅ 0.76 m

6 0

3 years ago

a female vocalist with a soprano voice can sing as high as 1000 hz. given that the speed of sound is 345 m/s what is the wavelen

Neporo4naja [7]

0.345 m.

<h3>Explanation</h3>

The wavelength is the distance that the wave travels in each cycle. The wave travels 345 meters in each second. Let the wavelength of this wave be $\lambda$ . That's the distance the wave travels in one cycle.

The frequency of the sound wave is 1 000 Hz, meaning that there are 1 000 cycles in each second. The wave travels a distance of 1 000 wavelengths in one second. That would be a distance of $1,000\;\lambda$ .

From the speed of the wave, the wave travels 345 meters in one second. In other words,

$1,000\;\lambda = 345$ .

$\lambda = \dfrac{345}{1,000} = 0.345\;\text{m}$ .

To generalize:

$\lambda = \dfrac{v}{f}$ ,

where

$\lambda$ wavelength of the wave,
$v$ the speed of the wave, and
$f$ the frequency of the wave.

3 0

3 years ago

Mass is 56.8 g and the volume is 10 mL what is the density

scoundrel [369]

Answer: 5.68g/ML.

Explanation; Divide the mass of the unknown substance and the volume of the unknown substance and you will have your answer.

Hope this helps! ^^ if you can pls mark me brainiest!

6 0

2 years ago

The mass of objects is 4kg and it has a density of 5gcm^-3. what is the volume

Yanka [14]

Answer:

4kg×5gm^3=60

Explanation:

the object if heavy

8 0

2 years ago