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IgorC [24]
2 years ago
7

A thin layer of liquid methylene iodide (n = 1.756) is sandwiched between two flat, parallel plates of glass (n = 1.50). What mu

st be the thickness of the liquid layer if normally incident light with λ = 675 nm in air is to be strongly reflected?
Physics
1 answer:
Harrizon [31]2 years ago
5 0

Answer:

t = 96.1 nm

Explanation:

For strong reflection through liquid layer we know that the path difference between two reflected light rays must be integral multiple of wavelength

now we know that the path difference of two reflected light from thin liquid layer is given as

2\mu t - \frac{\lambda}{2} = N\lambda

here we know that

\mu = 1.756

t = thickness of layer

N = 0 (for minimum thickness of layer)

\lambda = 675 nm

now we have

2(1.756) t = \frac{675 nm}{2}

t = 96.1 nm

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Read 2 more answers
90cm uniform lever has a load 30N suspended at 15cm from one of it's end. If the fulcrum is at the center of gravity. The force
solniwko [45]

Answer: F = 20 N

Explanation:

I will ASSUME that the fulcrum is at the center of gravity of the lever arm, This means that the lever arm itself creates no moment about the fulcrum because there is no moment arm for that particular force.

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The easiest convenient point is the fulcrum

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3 0
2 years ago
A 8.0 µF capacitor is initially connected to a 2.0 V battery. Once the capacitor is fully charged the battery is removed and a 6
aalyn [17]

Answer:

I = 0.451 amp

Explanation:

given,

C = 8.0 µF

V = 2 V

resistor connected between two terminal = 6 Ω

current flowing through resistor = 13 µsec

Q = CV

Q = 8 x 2

Q = 16 µC                              

for an RC discharge circuit

V = V_0e^{-\dfrac{t}{RC}}

I = \dfrac{-Q_0}{RC}e^{-\dfrac{t}{RC}}

t =  13 µsec

I = \dfrac{-16}{6\times 2}e^{-\dfrac{13}{6\times 2}}

I = 0.451 amp

neglecting  -ve sign just to show direction.

3 0
3 years ago
An electromagnet produces a magnetic field of 0.520 T in a cylindrical region of radius 2.40 cm between its poles. A straight wi
koban [17]

Answer:

Magnetic force, F = 0.262 N

Explanation:

It is given that,

Magnetic field of an electromagnet, B = 0.52 T

Length of the wire, l = 2r =2\times 2.4=4.8\ cm=0.048\ m

Current in the straight wire, i = 10.5 A

Let F is the magnitude of force is exerted on the wire. The magnetic force acting on an object of length l is given by :

F=ilB

F=10.5\ A\times 0.048\ m\times 0.52\ T

F = 0.262 N

So, the magnitude of force is exerted on the wire is 0.262 N.

3 0
2 years ago
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