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Viefleur [7K]
4 years ago
11

Which statement is true about acceleration?

Physics
2 answers:
dmitriy555 [2]4 years ago
6 0
C is the correct answer.
Alja [10]4 years ago
6 0
Acceleration is always the rate of change of velocity per unit time.  ( C. )

Notice that a change of direction is a change of velocity,
even if speed doesn't change.

This means that acceleration can take place even if speed isn't changing.
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Convert 285,000 milliliters to decaliters.​
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The answer is 28.5 decaliters. Hope this helps
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Read 2 more answers
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seraphim [82]

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Any fracture or system of fractures along which Earth moves is known as a
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3 years ago
Oil having a specific gravity of 0.9 is pumped as illustrated with a water jet pump. The water volume flowrate is 1 m3 /s. The w
love history [14]

Answer:

The rate at which the pump moves oil is 1 m³/s

Explanation:

Assumptions:

  • there is steady-state flow
  • oil and water are incompressible
  • first fluid is water, second fluid is oil and third fluid is the mixture of oil and water.

\rho_1Q_1 + \rho_2Q_2 = \rho_3Q_3 -------equation (i)

where;

ρ is the fluid density

Q is the volumetric flow rate

Q_1 + Q_2 = Q_3--------equation (ii)

Substitute in Q₃ in equation i

\rho_1Q_1 + \rho_2Q_2 = \rho_3(Q_1 +Q_2)

divide through by ρ₁

\frac{\rho_1Q_1}{\rho_1}+ \frac{\rho_2Q_2}{\rho_1} =\frac{ \rho_3(Q_1 +Q_2)}{\rho_1}\\\\Note; \frac{\rho_2}{\rho_1} = \gamma_2 \ and \ \frac{\rho_3}{\rho_1} = \gamma_3\\\\Q_1 + \gamma_2Q_2 = \gamma_3(Q_1+Q_2)

Make Q₂ the subject of the formula

Q_2 = \frac{Q_1(1- \gamma_3)}{\gamma_3-\gamma_2} = \frac{1 (\frac{m^3}{s}) (1-0.95)}{0.95-0.9} = 1 \ \frac{m^3}{s}

Therefore, the rate at which the pump moves oil is 1 m³/s

6 0
3 years ago
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