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3 years ago

Does a bottle of acetic acid contain a solid or a liquid on a chilly morning with the window open and the laboratory at 10 ∘ C ?

Chemistry

1 answer:

Fofino [41]3 years ago

7 0

Answer is: a bottle of acetic acid contains a solid.

Acetic or ethanoic acid (CH₃COOH) when undiluted is called glacial acetic acid.

Glacial acetic acid has freezing point (melting point) around 16.6°C, so it will be at solit state.

Vinegar is mixture of acetic acid (CH₃COOH) and water (H₂O). Vinegar is colourless liquid with sour taste and pungent smell, freezing point of the vinegar is lower than glacial acetic acid.

Acetic acid dissociate in aqueous solution to form hydrogen ions (H⁺) and acetic anion (CH₃COO⁻).

Balanced chemical reaction (dissociation):

CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).

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15 grams of HCl should theoretically produce 0.42 grams of H2. The reaction actually produced 0.15 grams of H2. What is the perc

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Answer:

35.7%

Explanation:

The percent yield is calculated by the formula:

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4 years ago

(A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered

FrozenT [24]

Answer:

1) 0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

2) The mass % calcium carbonate in the tablet is 50.58%.

3) The mass % of calcium in calcium carbonate is 40.00 %.

4) Mass of calcium in a tablet is 0.33 g.

Explanation:

Mass of tablet = 1.631 g

Mass of the watch glass = 46.719 g

Mass of the watch glass + mass of calcium carbonate = 47.544 g.

Mass of calcium carbonate = 47.544 g - 46.719 g = 0.825 g

0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

Mass of calcium carbonate = 0.825 g

Percentage of calcium in tablet:

$\%=\frac{\text{Mass of calcium carbonate }}{\text{Mass of tablet}}\times 100$

$\%=\frac{0.825 g}{1.631 g}\times 100=50.58\%$

The mass % calcium carbonate in the tablet is 50.58%.

Percentage of calcium in calcium carbonate :

Molar mass of calcium carbonate = 100 g/mol

Atomic mass of calcium = 40 g/mol

Percentage of calcium in calcium carbonate :

$\%=\frac{\text{atomic mass of calcium}}{\text{Molar mass of}CaCO_3}\times 100$

$\%=\frac{40 g/mol}{100 g/mol}\times 100=40.00\%$

The mass % of calcium in calcium carbonate is 40.00 %.

Mass of calcium carbonate = 0.825 g

The mass % of calcium in calcium carbonate is 40.00 %.

Mass of calcium in a tablet : x

$40.00\%=\frac{\text{Mass of calcium in a tablet}}{0.825 g}\times 100$

$x=40.00\times \frac{0.825 g}{100}=0.33 g$

Mass of calcium in a tablet is 0.33 g.

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