All categories

3 years ago

Does a bottle of acetic acid contain a solid or a liquid on a chilly morning with the window open and the laboratory at 10 ∘ C ?

Chemistry

1 answer:

Fofino [41]3 years ago

7 0

Answer is: a bottle of acetic acid contains a solid.

Acetic or ethanoic acid (CH₃COOH) when undiluted is called glacial acetic acid.

Glacial acetic acid has freezing point (melting point) around 16.6°C, so it will be at solit state.

Vinegar is mixture of acetic acid (CH₃COOH) and water (H₂O). Vinegar is colourless liquid with sour taste and pungent smell, freezing point of the vinegar is lower than glacial acetic acid.

Acetic acid dissociate in aqueous solution to form hydrogen ions (H⁺) and acetic anion (CH₃COO⁻).

Balanced chemical reaction (dissociation):

CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).

You might be interested in

Is the following chemical equation balanced? 4Al + 3O2 2Al2O3 yes no

PolarNik [594]

Answer:

Yes!

Explanation:

4Al + 3O2 -> 2Al2O3

4 Al's on the left side

6 O's on the left side

4 Al's on the right side

6 O's on the left side

This is balanced! Let me know if you need help with any other equations.

4 0

3 years ago

Read 2 more answers

How many atoms of oxygen are in 1.00 mole of Cu(NO3)2 ?

vova2212 [387]

Answer:

1 mole of 02=6.022*10^23 02 molecules 1 02 molecules

Explanation:

SANA MAKATULONG PO ♥️♥️

3 0

3 years ago

When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.

MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

$\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)$

where,

$\Delta H$ = change in enthalpy = ?

C = heat capacity of water = $4.18J/g.K$

m = total mass of sample = 2.174 + 127.4 = 129.6 g

$T_1$ = initial temperature = $23^oC=273+23=296K$

$T_2$ = final temperature = $37.1^oC=273+37.1=310.1K$

Now put all the given values in the above expression, we get:

$\Delta H=mC(T_2-T_1)$

$\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J$

Now we have to calculate the moles of AX added to water.

$\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles$

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = $\frac{7638.36}{0.04592}=166340.59J=166.34kJ$

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

7 0

3 years ago

Beet juice is added to a unknown solution and changes color from red to purple. Curry powder, added to the same solution, turns

Nutka1998 [239]

Answer:

The unknown liquid has low H+ concentrations and high OH- concentrations.

Explanation:

3 0

4 years ago

How many watts would equal 137 kilowatts?

natka813 [3]

Answer:

137,000 watts

Explanation:

1 kilowatt = 1000 watts

137 kilowatts = 1000 × 137 watts

= 137,000 watt

5 0

3 years ago

Read 2 more answers