Pe=1/2Kx^2
Half times spring constant times distance squared over time
Ans is <span>I. Flowing groundwater that dissolves rock , such as limestone</span>
Answer:
80×5×10=4000J
so therefore, work done on the body is 4000J
To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description, which determine the velocity, such as the displacement of a particle as a function of time, that is to say
![v = \frac{x}{t}\rightarrow x = v*t](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bx%7D%7Bt%7D%5Crightarrow%20x%20%3D%20v%2At)
Where,
x = Displacement
v = Velocity
t = Time
Our values are given as,
![v=3*10^8m/s](https://tex.z-dn.net/?f=v%3D3%2A10%5E8m%2Fs)
![t = 1.33 s](https://tex.z-dn.net/?f=t%20%3D%201.33%20s)
Replacing we have that,
![x=v*t](https://tex.z-dn.net/?f=x%3Dv%2At)
![x=(3*10^8)(1.33)](https://tex.z-dn.net/?f=x%3D%283%2A10%5E8%29%281.33%29)
![x = 399'000.000m](https://tex.z-dn.net/?f=x%20%3D%20399%27000.000m)
Therefore the distance from Earth to the Moon is 399.000 km